复数的算术运算

Arithmetic operations on Complex Numbers

本文关键字：算术运算      更新时间：2023-10-16

这是我在结果中面临的错误我正在尝试制作一个程序 从用户那里获取两个复数，然后在输出中显示这些数字的加法、减法和乘法 我在下面提供了 mY 代码，但它没有显示正确的输出 我已经尝试了很多 但它不起作用 一点帮助将不胜感激

#include<iostream>
using namespace std;
class complexnumber
{
int real, image;
public:
{
real = real;
image = image;
}
complexnumber operator +(complexnumber c2)
{
complexnumber temp;
temp.real = real + c2.real;
temp.image = image + c2.image;
return temp;
}
complexnumber operator-(complexnumber c2)
{
complexnumber temp;
temp.real = real - c2.real;
temp.image = image - c2.image;
return temp;
}
complexnumber operator*(complexnumber c2)
{
complexnumber temp;
temp.real = real * c2.real + (image *c2.image)*(-1);
temp.image = image * c2.real+c2.image*real;
return temp;
}
void display(complexnumber c)
{
if (c.image < 0)
{
cout << real <<  image << "i";
}
else
{
cout << real << "+" << image << "i";
}
}
};
int main()
{
int real1, real2, image1, image2;
cout << "enter real value 1:";
cin >> real1;
cout << endl;
cout << "enter real value 2:";
cin >> real2;
cout << endl;
cout << "enter imaginary value 1:";
cin >> image1;
cout << endl;
cout << "enter imaginary value 2:";
cin >> image2;
cout << endl;
complexnumber c1, c2, c3, c4, c5;
c1.set(real1, image1);
c2.set(real2, image2);
c3 = c1 + c2;
c4 = c1 - c2;
c5=c1*c2;
cout << "addition of two complex number       ";
c3.display(c3);
cout << endl;
cout << "subtraction of two complex number    ";
c4.display(c4);
cout << endl;
cout << "multiplication of two complex number ";
c5.display(c5);
cout << endl;
return 0;
}

public:
{
real = real;
image = image;
}

我假设这是您在 main 中调用的set函数

public:
void set(int real, int image){
real = real;
image = image;
}

这里不是将成员变量设置为real，image功能set参数值。这只是将传递的变量赋值回自身。编译器将首先查找名为"real"的局部变量或构造函数参数，只有当它找不到时，它才会开始寻找名为"real"的类成员。结果是上面的语句 "real=real" 会将存储在参数 "real" 中的值分配给参数 "real"，使其成为无用的语句。

public:
void set(int real, int image){
this->real = real;
this->image = image;
}

这将获得所需的输出。

这段代码很有帮助:)

int real, image;
public:
void set(int real, int image)
{
this->real = real;
this->image = image;
}
complexnumber operator +(complexnumber c2)
{
complexnumber temp;
temp.real = real + c2.real;
temp.image = image + c2.image;
return temp;
}
complexnumber operator-(complexnumber c2)
{
complexnumber temp;
temp.real = real - c2.real;
temp.image = image - c2.image;
return temp;
}
complexnumber operator*(complexnumber c2)
{
complexnumber temp; 
temp.real = real * c2.real + (image *c2.image)*(-1);
temp.image = image * c2.real+c2.image*real;
return temp;
}
void display()
{
if (this->image < 0)
{
cout << this->real <<  this->image << "i";
}
else
{
cout << this->real << "+" << this->image << "i";
}
} }; int main() {
int real1, real2, image1, image2;
cout << "enter real value 1:";
cin >> real1;
cout << endl;
cout << "enter real value 2:";
cin >> real2;
cout << endl;
cout << "enter imaginary value 1:";
cin >> image1;
cout << endl;
cout << "enter imaginary value 2:";
cin >> image2;
cout << endl;
complexnumber c1, c2, c3, c4, c5;
c1.set(real1, image1);
c2.set(real2, image2);
c3 = c1 + c2;//(1+3i)+(2+4i)
c4 = c1 - c2;//(1+3i)-(2+4i)
c5= c1 * c2; //(1+3i)(2+4i) = (1)(2)+(1)(4i)+(3i)(2)+(3i)(4i) 
//              = (2) +(4i)+(6i)(12i^2)
//              = 2+10i+12i^2
//(i^2 == -1)   = 2 + 10i-12 = -10+10i
cout << "addition of two complex number       ";
c3.display();//Dont need to pass object. Its already has c3 object
cout << endl;
cout << "subtraction of two complex number    ";
c4.display();
cout << endl;
cout << "multiplication of two complex number ";
c5.display();
cout << endl;
return 0; }

如有任何澄清，请告诉我:)

相关文章：