基于数据集合执行二叉树搜索
Perform binary trees search based a collection of data
我被要求为具有x, y和z坐标的数据集合编写BTS代码，其中有负数和正数，要求如下:
-
该程序能够基于数据集执行二叉树搜索。
-
请使用此邮件中提供的数据。它是X,Y, Z坐标的集合
- 该程序必须能够:
- 查找正X，负X，正y，负y，正z，负z。
- 用户可以搜索所有正数、所有负数等。
所以用户会输入一个X坐标，它会在输出中同时显示Y和Z，另一个是当用户想要搜索所有X的正/负时，它也会在X中显示Y和Z。到目前为止，我只知道二进制搜索只能对单个数字执行搜索，但不能对包含3个数字的元素字符串执行搜索。
这是X, Y和Z数据的集合，例如:
-0.090729 0.122568 0.030209 <--- one line of X Y Z coordinate
-0.179660 0.154953 0.033881
-0.335793 0.244996 0.269589
0.075957 0.149626 0.114472
我也将使用这段代码作为基础
#include <cstdlib>
#include <iostream>
using namespace std;
int binary_search(int array[],int first,int last, int value);
int main() {
int list[10];
for (int k=0; k<11; k++)
list[k]=2*k+1;
cout<< "binary search results: "<< binary_search(list,1,21,11)<<endl;
return 0;
}//end of main
int binary_search(int array[],int first,int last, int search_key)
{
int index;
if (first > last)
index = -1;
else
{
int mid = (first + last)/2;
if (search_key == array[mid])
index = mid;
else
if (search_key < array[mid])
index = binary_search(array,first, mid-1, search_key);
else
index = binary_search(array, mid+1, last, search_key);
} // end if
return index;
}// end binarySearch
我还认为使用数组是不够的，我将不得不做一个单独的文件，像一个数据库，用户可以用一个输入搜索数据。所以我有一个想法，我只做二叉树的X坐标但当用户输入X时，它会显示Y和Z与数据收集的X，数据收集也很多，任何专家的帮助将不胜感激:)仍然想知道二叉搜索树是否能够做到这一点....
所以这是我需要使用的数据集合，有人能告诉我如何使该函数能够从这个庞大的集合调用数据吗?
0.075957 0.149626 0.114472
0.000905 0.131220 0.031000
0.334059 -0.004790 0.207368
0.380561 -0.016845 0.110792
-0.083847 -0.009495 0.260374
0.316664 0.071467 0.120474
-0.307909 0.341245 -0.115581
0.411077 -0.098945 0.029724
-0.093728 0.413972 -0.045792
-0.445182 0.173948 0.306924
-0.339452 0.094466 0.338246
0.154974 0.153764 0.113986
0.383043 -0.017294 0.038540
0.371618 -0.036996 -0.034430
-0.488796 0.174331 0.109211
-0.425485 -0.003917 0.201166
-0.328634 0.319858 0.114390
-0.410262 0.298180 0.193996
0.155009 0.097454 0.225033
-0.225622 0.246139 0.118317
-0.399749 0.163849 0.335552
0.076578 0.133341 0.177679
-0.201047 0.142376 0.174390
-0.429153 -0.098775 -0.040573
0.230882 0.131755 0.118676
-0.483743 0.082920 0.040329
-0.078715 0.471042 -0.055900
-0.411718 0.237937 0.278383
-0.005249 0.003769 0.270521
-0.018101 0.489653 -0.124951
-0.133572 0.398057 -0.090000
0.154095 0.134174 0.180583
-0.172136 0.147088 0.112057
0.240332 0.079992 0.210373
-0.175250 0.391765 0.011504
-0.477955 0.162864 0.042821
-0.263429 0.246060 0.204495
0.408153 -0.094551 0.112774
0.388142 -0.103007 0.184936
-0.257106 0.309349 0.107726
-0.020619 0.343770 -0.051245
-0.366778 -0.278556 0.116261
-0.329815 0.313916 0.034602
-0.482418 0.071724 0.268572
0.296142 0.067455 0.185325
0.392588 -0.106540 -0.040632
-0.348415 0.380318 -0.132477
0.074743 0.098941 0.226089
0.313984 -0.095701 0.274736
-0.000127 0.359321 -0.099978
-0.389304 0.419894 -0.275472
-0.448952 -0.015681 0.018614
0.360441 0.017741 0.133138
0.072016 -0.429793 0.306404
0.157903 -0.423369 0.305657
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0.021908 0.122344 0.172256
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-0.333589 0.232102 -0.053896
0.240226 -0.009687 0.271713
-0.125529 0.419457 -0.000220
-0.323461 0.062386 -0.069065
-0.335525 0.413992 -0.292639
-0.485317 0.253072 0.122003
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0.320594 -0.097082 -0.121452
0.153275 -0.012350 0.284012
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0.155106 0.152666 0.034476
0.237370 -0.432505 0.276914
0.213352 -0.110928 0.333017
0.076081 0.050562 0.261882
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0.304469 0.060476 -0.029716
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0.122461 -0.463743 0.002471
0.076974 -0.458785 0.035224
-0.165019 -0.485403 0.035211
-0.002507 -0.458952 0.035797
0.305050 -0.475313 0.120096
-0.248056 -0.489990 0.034763
-0.072565 -0.460061 0.025380
0.109360 -0.475999 0.064561
0.243323 -0.479673 0.126123
-0.110629 -0.489074 0.043599
0.151045 -0.483545 0.115056
0.113069 -0.479908 0.084853
0.336442 -0.463570 0.135023
0.076638 -0.459867 0.113200
-0.117317 -0.480495 0.113990
-0.002076 -0.459748 0.113895
-0.057473 -0.462636 0.113188
-0.256639 -0.489621 0.112012
0.123161 -0.463285 0.143835
0.181877 -0.477548 0.192178
0.151977 -0.457373 0.192210
0.076190 -0.455132 0.193957
-0.102975 -0.477424 0.189320
-0.067928 -0.459351 0.209563
-0.002745 -0.457144 0.191918
-0.161571 -0.485037 0.194232
0.216362 -0.476830 0.268931
-0.250727 -0.485793 0.193098
-0.320925 -0.308279 0.034877
0.072334 -0.480626 0.296205
-0.087828 -0.482461 0.282326
-0.003897 -0.482100 0.299386
int main ()
{
{
ifstream myReadFile;
myReadFile.open("Data.txt");
char output[100];
if (myReadFile.is_open())
{
while (!myReadFile.eof())
{
myReadFile >> output;
cout<<output;
}
}
myReadFile.close();
return 0;
}
这是顶点X的冒泡排序，我知道排序要花很长时间，但时间不重要，只要代码能工作就行
for (i=0; i<500-1; i++)
for (int j=i+1; j<500; j++)
if (X[i] > X[j])
{
int temp = X[i];
X[i] = X [j];
X[j] = temp;
temp = Y[i];
Y[i] = Y [j];
Y[j] = temp;
temp = Z[i];
Z[i] = Z [j];
Z[j] = temp;
}
您谈论的是二叉搜索树，但您所展示的代码是在排序数组上进行二叉搜索。这不是一回事。
使用二进制搜索的一种方法是将X,Y和Z值放在一个数组或自定义结构体中。比如:struct Vertex {
float X;
float Y;
float Z;
};
修改你的二进制搜索函数，使它接受这些结构体的数组而不是整数数组。您必须使您的搜索关键字的X浮动值:
int binary_search(Vertex array[],int first,int last, float x_value);
将X, Y, Z值加载到Vertex的数组中，然后按X值排序:
bool vertexXComparator(const Vertex& lhs, const Vertex& rhs) {
return lhs.X < rhs.X;
}
std::sort(list, list+number_of_vertexes, vertexXComparator);
那么你应该能够在排序列表上使用二进制搜索(或std::binary_search)。
我对使用浮点数作为搜索键有点谨慎。测试浮点数是否相等通常不是一个好主意。
现场演示。
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