二进制搜索树叶数问题

我迫切需要帮助来查找代码中的问题，我确信它已经缩小到countLeaves函数。无论我如何修改，我似乎都无法将其打印出来。我对C++很陌生，但我真的很感激任何人能为我提供的东西！我将按照这个顺序发布标题、函数和main。

#include <iostream>
//#include<stack>
//#include<queue>
#ifndef BSTFunction
#define BSTFunction
using namespace std;
typedef int num;
class Node{
public:
num info;
Node* left;
Node* right;
Node(); // Valuetype to num
Node(num);
};
class BST{
public:
Node* findNode(num);
Node* findParent(num);
Node* findrightnode(Node*);
void inorder(Node*);
Node* root;
Node* curr;
//Was public:
BST();
void insert(num);
void inorderTraversal(); //was traverse
num search();
void custom_print();
int countLeaves(Node* T);
};
#endif

函数.cpp

#include <iostream>
#include <queue>
#include "BSTFunction.hpp"
Node::Node(){
left=right=NULL;
}
Node::Node(num val){
info=val;
left=right=NULL;
}
//constructor
BST::BST(){
root=curr=NULL;
}
//insert a node with value val in tree
void BST::insert(num val){
if(root==NULL)
root = new Node(val);
else{
Node* p =findNode(val);
if(p==0) {
//cout<<"fine1";
Node* parent=root;
if (p != root)
parent = findParent(val);
if(val>parent->info) parent->right=new Node(val);
else parent->left=new Node(val);
}//cout<<"fine2";
}
}
//remove the node if value is val
//fins node with a value key
Node* BST::findNode(num key){
Node* p =root;
while((p!=NULL)&&(p->info!=key)){
if(key<p->info)p=p->left;
else p=p->right;
}
return p;
}
//find parent of a node with value key
Node* BST::findParent(num key){
Node* p =root;
Node* q=0;
while((p!=NULL)&&(p->info!=key)){
q=p;
if(key<p->info)p=p->left;
else p=p->right;
}
return q;
}
//finds the most right of a node p(means immediate succesor of p in inorder representation)
//Node* BST::findrightnode(Node* p){
//    Node* righty=p;
//    while(righty->right!=NULL)
//        righty=righty->right;
//    return righty;
//}
void BST::inorder(Node* p){
if(p!=NULL){
inorder(p->left);
cout<<p->info<<" ";
inorder(p->right); }
}
void BST::inorderTraversal(){
cout<<endl<<"Inorder: ";
inorder(root);
cout<<endl;
}
//to print tree hightwise i.e. all nodes at h1, then all nodes at h2, then at h3
void BST::custom_print(){
//Node* temp;
if(root==NULL)
return;
queue<Node*> Q;
Q.push(root);
//Q.push(NULL);
while(!Q.empty()){
curr=Q.front();
cout<<curr<<" ";
Q.pop();
Q.push(curr->left);
Q.push(curr->right);
}
}

int BST::countLeaves(Node *T)
{
if(T ==NULL)      //if T is empty, return0
{
return(0);
}
else if(T -> left == NULL && T-> right == NULL)      //if T has0 children, then it is a leaf
{
return(1);
}
else
{
return countLeaves(T -> left) + countLeaves(T -> right);  //recursive call to find more leaves
}
}

主要.cpp

#include<iostream>
#include "BSTFunction.hpp"
int main()
{
BST leaves;
leaves.insert(24);
leaves.insert(43); //The code will take all of these numbers entered into the main function and put them in traversal order, much like it could under any order (post or pre) if needed. (Note to self: Not needed for this assignment)
leaves.insert(82);
leaves.insert(22);
leaves.insert(12);
leaves.insert(92);
leaves.insert(68);
leaves.insert(20);
leaves.insert(4);
cout << "These are the in order leaves for the Bianary Search Tree. " << endl;
leaves.inorderTraversal();
cout << "The number of leaves are: " << endl;
leaves.countLeaves()
//leaves.custom_print();
return 0;
}