与'operator='不匹配(操作数类型'String'且"void")

No match for 'operator=' (operand types are 'String' and 'void')

本文关键字:String 类型 void operator 不匹配 操作数      更新时间:2023-10-16

我正在查询一个使用NodeMCU ESP8266微控制器返回JSON字符串的网页。来自网页的响应如下所示:

{"1":true,"2":false,"3":false,"4":true,"5":true,"6":false,"7":false,"8":false}

我使用的代码如下所示:

#include <ESP8266WiFi.h>
#include <ESP8266HTTPClient.h>
#include <ArduinoJson.h>
String payload = "";
const char* ssid = "ssid";
const char* password = "password";
String url = "example.com/data.json";
void setup() {
Serial.begin(115200);
delay(2000); while (!Serial);
WiFi.begin(ssid, password);
while (WiFi.status() !=WL_CONNECTED){
delay(500);
Serial.print(".");
}
Serial.println(WiFi.localIP());
pinMode(D0, OUTPUT);
}
void loop() {
StaticJsonBuffer<100> jsonBuffer;
delay(5000);
HTTPClient http;
http.begin(url);
int httpCode = http.GET();
Serial.println(httpCode);
Serial.println(http.getString());
if (httpCode > 0) {
payload = http.getString();
}
http.end();
JsonObject& root = jsonBuffer.parseObject(payload);
Serial.println(payload);
if(!root.success()) {
Serial.println("parseObject() failed");
}
if(root["1"] == true) {
Serial.println("true");
}
digitalWrite(D0, !digitalRead(D0));
}

我相信它无法解析的原因是有效载荷变量以尾随换行符结尾。然后我尝试payload = payload.trim();但后来我得到了no match for 'operator=' (operand types are 'String' and 'void')所以我尝试了同样的问题payload = payload.replace("n,"");然后我再次尝试payload = String(payload);失败。我做错了什么?

就像有人说的那样,trimreplace不会返回String。它"返回"void,错误消息告诉您正在尝试为字符串分配无效返回。放payload.trim();就足够了.payload.replace("n","");也是如此

但是payload.trim();payload.replace("n","");不会做同样的事情。如文档中所述,trim()删除尾随和前导空格,而replace("n","")将删除字符串中的所有(且仅(换行符,即使它位于中间。

空格通常是指空格、换行符、制表符和其他一些杂项字符。