C++ 从链表中删除项目时出现问题

C++ Issue with deleting item from linked list

本文关键字：问题 删除项目 链表 C++      更新时间：2023-10-16

上一个问题已解决！

新问题：代码本身。我一直在研究一个函数的代码，用于从链表中删除选定的项目，它可能出现多少次。但是，当我运行程序的该部分以尝试删除节点时，它只会结束程序。我知道有些事情肯定会关闭，但即使看这方面的教程，我也不太了解如何实现这个指令。任何帮助将不胜感激。[已解决]

功能

void LinkedList::deleteItem(int _newItem)
{
if(isEmptyList())
cout << "t<ERROR> List is empty.n";
else
{
bool itemDelete = false;
nodeType *q = first;
while(q != NULL)
{
if(first->info == _newItem)
{
nodeType *p = first->link;
first->link = p->link;
delete p;
--count;
itemDelete = true;
}
if(q->link->info == _newItem)
{
nodeType *r = q;
nodeType *p = q;
r = r->link;
p->link = r->link;
delete r;
--count;
itemDelete = true;
}
q = q->link;
}
if(itemDelete == true)
cout << "Item was deleted.";
else
cout << "Item was not found.";
}

}

类和结构

struct nodeType
{
int info;
nodeType *link;
};
class LinkedList
{
public:
void initializeList();
bool isEmptyList();
void printList();
int findLength();
void destroyList();
int infoFirst();
int infoLast();
bool searchItem(int);
void insertFront(int);
void insertBack(int);
void deleteItem(int);
int calcTotal();
int calcAvg();
LinkedList();
private:
nodeType *first, *last, *newNode;
int count; //adds or remove one whenever a node is added or removed
};

代码的一个问题是这一行：

if(q->link->info == _newItem)

您正在访问链表中的下一个链接，但下一个链接可能是 nullPTR：

if(q->link != nullptr && q->link->info == _newItem)

在访问其成员信息之前，您应该首先检查它是否为 nullptr。

您还应该考虑移动：

if(first->info == _newItem)
{
nodeType *p = first->link;
first->link = p->link;
delete p;
--count;
itemDelete = true;
}

在循环之外，因为如果您尝试删除的节点不是第一个节点，则每次进入循环时都会进行此检查，因为您首先检查的是节点，而不是用于循环链表的节点 q。

另外，请考虑使用 nullptr 而不是 NULL。

else
{
bool itemDelete = false;
nodeType *q = first;
if(first->info == _newItem)
{
nodeType *p = first->link;
first->link = p->link;
delete p;
--count;
itemDelete = true;
}
// by doing !itemDelete you will exit once you find the item
// or you won't enter the loop if the item was the first in the list
while(q != nullptr && !itemDelete)
{
if(q->link != nullptr && q->link->info == _newItem)
{
nodeType *r = q;
nodeType *p = q;
r = r->link;
p->link = r->link;
delete r;
--count;
itemDelete = true;
}
q = q->link;
}
if(itemDelete == true)
cout << "Item was deleted.";
else
cout << "Item was not found.";
}

此处的此部分可以进一步折叠：

// by doing !itemDelete you will exit once you find the item
while(q != nullptr && !itemDelete)
{
if(q->link != nullptr && q->link->info == _newItem)
{
nodeType *r = q;
nodeType *p = q;
r = r->link;
p->link = r->link;
delete r;
--count;
itemDelete = true;
}
q = q->link;
}

自：

// by doing !itemDelete you will exit once you find the item
while(q->link != nullptr && !itemDelete)
{
if(q->link->info == _newItem)
{
nodeType *r = q;
nodeType *p = q;
r = r->link;
p->link = r->link;
delete r;
--count;
itemDelete = true;
}
q = q->link;
}

我希望这对您有所帮助。

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