助推.测试检查结构是否相等

Boost.Test check if structs are equals

本文关键字：是否 结构 测试 检查 助推      更新时间：2023-10-16

我是Boost的新手。Visual Studio 2017测试。

我正在尝试用以下测试来测试一种方法：

#define BOOST_TEST_MODULE astroTimeTests
#include <boost/test/included/unit_test.hpp>
#include <ctime>
#include "../../AstroTime/Convert.h"
struct TestFixture
{
Convert convert_instance;
TestFixture()
: convert_instance()
{}
~TestFixture() = default;
};
BOOST_FIXTURE_TEST_SUITE(TestConvert, TestFixture)
BOOST_AUTO_TEST_CASE(julianToGreenWichCase)
{
// http://www.onlineconversion.com/julian_date.htm
tm day1 = { 12, 28, 16, 2, 10, 119, 0, 0, 0};
BOOST_REQUIRE_EQUAL(day1, convert_instance.JulianToGreenWich(2458790.18625f));
}
BOOST_AUTO_TEST_SUITE_END()

CCD_ 1从CCD_ 3返回一个CCD_。

但我做错了什么，因为我得到了以下错误：

错误C2678二进制'=='：找不到占用左手的运算符类型为"const Left"的操作数(或没有可接受的转换(

错误C2338类型必须实现运算符<lt；可打印

错误C2679二进制'<lt；'：找不到占用右手的运算符类型为"const T"的操作数(或没有可接受的转换(

如何测试两个值day1和JulianToGreenWich的结果是否相等？

这就是我修复这个错误的方法：

#define BOOST_TEST_MODULE astroTimeTests
#include <boost/test/included/unit_test.hpp>
#include <ctime>
#include <iostream>
#include "../../AstroTime/Convert.h"
struct TestFixture
{
Convert convert_instance;
TestFixture()
: convert_instance()
{}
~TestFixture() = default;
};
bool operator ==(tm const &left, tm const &right)
{
return(
left.tm_sec == right.tm_sec
&& left.tm_min == right.tm_min
&& left.tm_hour == right.tm_hour
&& left.tm_mday == right.tm_mday
&& left.tm_mon == right.tm_mon
&& left.tm_year == right.tm_year);
}
std::ostream& operator<<(std::ostream& os, const tm& dt)
{
os << dt.tm_hour << " " << dt.tm_min << " " << dt.tm_sec << ", "
<< dt.tm_mday << " " << dt.tm_mon << " " << (1900 + dt.tm_year) << std::endl;
return os;
}
BOOST_FIXTURE_TEST_SUITE(TestConvert, TestFixture)
BOOST_AUTO_TEST_CASE(julianToGreenWichCase)
{
// http://www.onlineconversion.com/julian_date.htm
tm day1 = { 12, 28, 16, 2, 10, 119, 0, 0, 0};
BOOST_REQUIRE_EQUAL(day1, convert_instance.JulianToGreenWich(2458790.18625f));
}
BOOST_AUTO_TEST_SUITE_END()
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