将 URL/href 从网络服务器重新派生到ESP8266(以处理它)

Retriveing URL/href from webserver to ESP8266 (to process it)

本文关键字:派生 ESP8266 处理 新派生 href URL 网络 服务器 网络服务      更新时间:2023-10-16

我制作了一个由 2 个下拉列表组成的 HTML 表单,其中包含多个选择和 4 个输入框,当我填写所有输入并按提交时,所有数据都显示在 URL 中。问题是,我想使用 String.replace(( 处理ESP8266(在 c++ 中(中 URL 的内容;然后最后将其发送回处理的网络服务器。

我只需要帮助获取 C++ 字符串的 URL,因为我知道如何完成其余的工作。

我环顾四周,对于这个简单的问题,我很惊讶我并没有真正找到那么多。但是,我找到了Server.arg((,但我不知道如何使用它。


C++ page:

#include <ESP8266WiFi.h>
#include <ESP8266WebServer.h>
#include <WiFiClient.h>
#include "PageBuilder.h"
#include "newGame.h"
int x = 0; 
int y = 10;
String score="test";
String score2="test2";
String refresh = "5";

#if defined(ARDUINO_ARCH_ESP8266)
ESP8266WebServer Server;
ESP8266WebServer  server;
#endif
String scoreSend(PageArgument& args) { 
return score;
}
String scoreSend2(PageArgument& args) { 
return score2;
}
const char html[] = "<div class="jumbotron"><div align="center"><h1 class="display-4" style="font-family: zetafonts-cinematografica-extrabold; font-size: 30px;" >{{SCORE}} {{SCORE2}} </h1></div></div>";

String rate(PageArgument& args) { 
return refresh;
}
const char rfs[] = "<meta http-equiv="refresh" content="{{REFRESH}}">";
PageElement refresh_elm(rfs, { {"REFRESH", rate} });
PageElement body_elem(html, { {"SCORE", scoreSend} });
PageElement Score_2(html, { {"SCORE2", scoreSend2} });
PageElement CURRENT_GAME_ELEMENT(htmlPage2);
PageBuilder CURRENT_GAME("/current-game", { CURRENT_GAME_ELEMENT, body_elem, Score_2, refresh_elm});
PageElement NEW_GAME_ELEMENT(htmlPage3);
PageBuilder NEW_GAME("/new-game", {NEW_GAME_ELEMENT});
void setup() {
Serial.begin(115200);
pinMode(2, INPUT);
WiFi.softAP("ssid", "pass");
delay(100);       
CURRENT_GAME.insert(Server);     
NEW_GAME.insert(Server);        
Server.begin();
}
void loop() {
Server.handleClient();
}

Html page:
const char htmlPage3[] PROGMEM = R"=====(
<form id="what-team">
<div class="form-row">
<div class="col" style="float: left; padding-left: 5%;">
<label class="mr-sm-2 sr-only" for="inlineFormCustomSelect">Preference</label>
<select name="team1-playing-as" form="what-team" class="custom-select mr-sm-2" id="inlineFormCustomSelect" style="width:700px;height:50px;">
<option selected="">Choose Team</option>                    
<option value="manchester-united">Manchester United</option>
<option value="liverpool">Liverpool</option>
<option value="fc-barcelona">FC-Barcelona</option>
</select>
<div class="form-group">
<input type="Name" class="form-control" name="player1" value="" placeholder=" Player 1" style="width:700px;height:50px;">
<input type="Name" class="form-control" name="player2" value="" placeholder=" Player 2" style="width:700px;height:50px;">
</div>
</div>
<div class="col" style="float: right; padding-left: 5%;">
<label class="mr-sm-2 sr-only" for="inlineFormCustomSelect">Preference</label> 
<select name="team2-playing-as" form="what-team" class="custom-select mr-sm-2" id="inlineFormCustomSelect" style="width:700px;height:50px;">
<option selected="">Choose Team</option>
<option value="manchester-united">Manchester United</option>
<option value="liverpool">Liverpool</option>
<option value="fc-barcelona">FC-Barcelona</option>
</select>
<div class="form-group">
<input type="Name" class="form-control" name="player1" value="" placeholder=" Player 1" style="width:700px;height:50px; text-align: right;">
<input type="text" class="form-control" name="player2" value="" placeholder=" Player 2" style="width:700px;height:50px; text-align: right;">
</div>
</div>
</div>
<div style="padding-top: 50px; padding-left: 10%; padding-right: 10%; float: center;">
<input type="submit" value="Start" class="btn btn-primary btn-lg btn-block">
</div>
</form>
)=====";

这是我填写表格并按提交按钮时得到的 URL。"192.168.0.1/new-game?team1-playing-as=manchester-united&player1=John&player2=Doe&team2-playing-as=liverpool&player1=Doe&player2=John "

简而言之,我想做的是我想把它^ href变成一个字符串

编辑/更新:

我找到了一些方法,但是第一个只返回它得到的href,与server.hasarg((相同的功能,后者只返回元素的href,基本上,两者都只返回/new-game?。不幸的是,我想要/新游戏之后的东西?

bool func(HTTPMethod method, String uri) {
if (uri == "/new-game") {
Serial.println(uri);
return true;
} else {
Serial.println(uri);
return false;
}
}
const char* data = NEW_GAME.uri()

这是我从表单中检索数据所做的:


int h = 1;
void handleForm() {
String team1Team = Server.arg("team1-playing-as");
String team1P1   = Server.arg("player1");
String team1P2   = Server.arg("player2");
String team2Team = Server.arg("team2-playing-as");
String team2P3   = Server.arg("player3");
String team2P4   = Server.arg("player4");
if ((Server.args() == 6) && ( h == 1)) {
Serial.println("Team 1: " + team1Team);
Serial.println("Player 1: " + team1P1);
Serial.println("player 2: " + team1P2);
Serial.println("Team 2: " + team2Team);
Serial.println("Player 3: " + team2P3);
Serial.println("Player 4: " + team2P4);
delay(1000);
h = 0;
//-------------------this is where I want to redirect from /new-game to /current-game
}
if ((Server.args() == 0) && ( h == 0)) {
h = 1;
}
}

我通过这样做来重定向网站:const char rDIR[] = "<meta http-equiv="Refresh" content="0; url={{rDir}}">";,然后在这是真的时用/current-game替换{{rDIR}}if ((Server.args() == 6) && ( h == 1))

但是,我保存在字符串中的表单输入中的数据是正确的,当我尝试使用相同的方法(应该有效(接近时,字符串是空的......这真的很奇怪,因为它只有这样定义的字符串:String team1P1 = Server.arg("player1");不会将其值返回给令牌。