在 C++98 中,'dvd1' 必须由构造函数初始化,而不是由 '{...}' 初始化

In C++98 'dvd1' must be initialized by constructor, not by '{...}'

本文关键字:初始化 C++98 dvd1 构造函数      更新时间:2023-10-16

如何初始化 dvd1?

C:UsersSuperUserGoogle Drive>g++ -o a Question1.cpp

问题 1.cpp:在函数 'int main((' 中:

问题 1.cpp:39:76:错误:在 C++98 中,"dvd1"必须由构造函数初始化,而不是由"{...}"初始化

dvd dvd1 = {"僵尸","BBC","詹姆斯","英语","Alw",2012,20170601,20170630};

#include <iostream>
#include <string>
using namespace std;
class dvd
{
string movieName,movieProdComp,movieLeadActor,movieLanguage,renterName;
int releaseYear,rentDate,returnDate;
public:

dvd(string mn,string mpc,string mla,string ml, string rn,int ry,int rd,int retd);
void print();
};
dvd::dvd(string mn,string mpc,string mla,string ml, string rn, int ry,int rd,int retd){
movieName=mn;
movieProdComp=mpc;
movieLeadActor=mla;
movieLanguage=ml;
renterName=rn;
releaseYear=ry;
rentDate=rd;
returnDate=retd;
}
void dvd::print(){
cout<<"Movie:"<<movieName<<endl;
cout<<"Production:"<<movieProdComp<<endl;
cout<<"Starring:"<<movieLeadActor<<endl;
cout<<"Language:"<<movieLanguage<<endl;
cout<<"Rented By:"<<renterName<<endl;
cout<<"Released:"<<releaseYear<<endl;
cout<<"Rent Date:"<<rentDate<<endl;
cout<<"Return Date:"<<returnDate<<endl;
}
int main(){
dvd();
dvd dvd1 = {"Zombie","BBC","James","English","Alw",2012,20170601,20170630};
dvd1.print();
}

这称为列表初始化,对于非聚合类型,仅在 C++11 中受支持:

dvd dvd1 = {"Zombie","BBC","James","English","Alw",2012,20170601,20170630};

对于 C++98,您可能希望稍微更改它,像往常一样调用构造函数:

dvd dvd1("Zombie","BBC","James","English","Alw",2012,20170601,20170630);

>dvd是一种非聚合类型,在支持列表初始化的 C++11 之前无法使用支持初始化的初始化器进行初始化。(更准确地说,您要做的是复制列表初始化。

对于 C++98,您可以写

dvd dvd1 ("Zombie","BBC","James","English","Alw",2012,20170601,20170630);
dvd dvd1 = dvd("Zombie","BBC","James","English","Alw",2012,20170601,20170630);

在 C++98 中,只有当聚合类型是聚合类型时,才能像dvd dvd1 = {...};一样使用聚合初始化;在这种情况下,dvd具有用户定义的构造函数

,然后不使用它。