我创建了deque<CObject*>并添加了不同类型的元素。如何更改此元素的属性？

I created deque<CObject*> and added different type of element. How can I change attribute of this elements?

本文关键字：元素 属性 同类型 何更改 lt deque 创建 CObject 添加 gt      更新时间：2023-10-16

我创建了：

class CMap:{
public
std::deque<CObject*> obiekty;
}

class CBullet{
public:
int damage;
}

我添加了不同类型的元素(例如 唔唔�� 我想要使用 deque 更改属性

for( size_t i=0; i<game->Mapa->obiekty.size(); i++){
if(typeid(*(game->Mapa->obiekty[i]))==typeid(CBullet)){                                       
this->HP=this->HP - game->Mapa->obiekty[i] (?? my problem/I can't do it ?? ->damage); 
}
}

首先你需要从基类(CObject(继承你的派生类(CBullet，CTank(，像这样

//Base clase
class CObject
{
public:
//...
virtual ~CObject(){}; // Don't forget about virtual desctructor
};
class CBullet: public CObject
{
public:
//...
~CBullet(){};
void DoBulletMethod(){};
};
class CTank: public CObject
{
public:
//...
~CTank(){};
void DoTankMethod(){};
};

然后你可以通过dynamic_cast检查所有对象，如下所示：

for( size_t i=0; i< game->Mapa->obiekty.size(); i++)
{
if(dynamic_cast<CBullet*>(game->Mapa->obiekty[i]) != nullptr)
{
CBullet * BulletObj = dynamic_cast<CBullet*>(game->Mapa->obiekty[i]);
BulletObj->DoBulletMethod();
}
else if(dynamic_cast<CTank*>(game->Mapa->obiekty[i]) != nullptr)
{
CTank * TankObj = dynamic_cast<CTank*>(game->Mapa->obiekty[i]);
TankObj->DoTankMethod();
}
}

或者，您可以使用多态性并创建虚拟方法，而无需进一步检测当前对象类型，例如在基类中创建一个虚拟方法并在派生类中重写它：

//Base clase
class CObject
{
public:
//...
virtual ~CObject(){}; // Don't forget about virtual desctructor
virtual void DoActionInLoop()
{
//No action in base class
}
};
class CBullet: public CObject
{
public:
//...
~CBullet(){};
virtual void DoActionInLoop() override
{
std::cout << "I am bullet I can do here my tasks" << std::endl;
}
};
class CTank: public CObject
{
public:
//...
~CTank(){};
virtual void DoActionInLoop() override
{
std::cout << "I am tank and I can do here my tasks" << std::endl;
}
};

然后只需在每个CObject*实例上调用此方法并获取多态性：

for( size_t i=0; i< game->Mapa->obiekty.size(); i++)
{
game->Mapa->obiekty[i]->DoActionInLoop();
}
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