使用 ifSteam 重载类模板中的<<

由于某种原因，我找不到正确的模板函数符号来重载我的类模板 Arr 与 ifstream...(流工作) 我真的很难弄清楚这一点...

这是我的代码：

#include <iostream>
using namespace std;
#include <fstream>
template<typename T, int N = 1>
class Arr {
T m_data[N];
public:
Arr(const T& initializer = 0) {   //only for context
for (int i = 0; i < N; i++)
m_data[i] = initializer;
};
Arr(initializer_list<T> values) {   //only for context
copy(values.begin(), values.end(), m_data);
};
~Arr() {};                        //only for context
T operator[](unsigned index) const {   //only for context
return m_data[index];
}
T& operator[](int index) {   //only for context
return m_data[index];
};
};
template <typename T, int N>        //OK
ostream& operator<<(ostream &os, const Arr<T, N>& v)
{
for (int i = 0; i < N; i++)
os << v[i] << ' ';
return os;
}
template<typename T, int N>       //OK
ofstream& operator<<(ofstream &os, const Arr<T, N>& v)
{
int i;
for (i = 0; i < N - 1; i++)
os << v[i] << ',';
os << v[i];
return os;
}
template<typename T, int N>     // NEVER REACHING HERE
T operator>>(ifstream &os, T v)
{
//not reading
}
template<typename T, int N>     //OK
ifstream& operator>>(ifstream &os, const Arr<T, N>& v)
{
for (int i = 0; i < N; i++)
os >> v[i];     //C2679 binary '>>': no operator found which takes a right-hand operand of type 'T' (or there is no acceptable conversion)
return os;
}

int main()
{
Arr<float, 9> numbers({ 1,2,3,4,5,6,7,8,9 });
cout << numbers;             // ok
ofstream outf;
outf.open("myStat.csv");
outf << numbers;             // OK(save numbers to file)
outf.close();
Arr<float, 9> numbers_load;
ifstream inf;
inf.open("myStat.csv");
inf >> numbers_load;      // the problem here(explanation below)
}

注意：numbers_load是Arr<T, N>所以inf >> loaded_players会调用
ifstream& operator>>ifstream &os, const Arr<T, N>& v)但随后会发生错误，因为编译器找不到T operator>>(ifstream &os, T v)。为什么？

任何帮助将不胜感激。