读取并输出二进制文件(C++）中位置的字节

Reading and outputting byte at position in binary file (C++)

本文关键字：位置 字节 C++ 输出 二进制文件 读取      更新时间：2023-10-16

我想从二进制(.bin)文件中读取一组256字节的数据，并将其存储到缓冲区中。然后，我想将这些字节中的每一个移动到一个由char向量组成的向量中。此外，我想读取向量中的char值，并获得该字节的二进制值的相应整数值。我就是这样处理的：

typedef unsigned char BYTE;
vector< vector<BYTE> > pMem (256, vector<BYTE> (256, '0'));
ifstream binStream;
binStream.open("BACKING_STORE.bin", ios::binary | ios::in );
// allocate memory:
char * buffer = new char [256];
binStream.seekg(0, binStream.beg);
binStream.read(buffer, 256);
for( i = 0; i < 256; i++ )
pMem[0][i] = buffer[i];
for( i = 0; i < 256; i++ )
{
cout << "Physical memory char contents at 0[" << i << "]: " << pMem[0][i] << endl;
int x = pMem[0][i];
cout << "Physical memory integer contents at 0[" << i << "]: " << x << endl;
}

但当我打印出这些值时，我会得到这样的结果：

Physical memory char contents at 0[237]: 
Physical memory integer contents at 0[237]: 0
Physical memory char contents at 0[238]: 
Physical memory integer contents at 0[238]: 0
Physical memory char contents at 0[239]: ;
Physical memory integer contents at 0[239]: 59
Physical memory char contents at 0[240]: 
Physical memory integer contents at 0[240]: 0
Physical memory char contents at 0[241]: 
Physical memory integer contents at 0[241]: 0
Physical memory char contents at 0[242]: 
Physical memory integer contents at 0[242]: 0
Physical memory char contents at 0[243]: <
Physical memory integer contents at 0[243]: 60
Physical memory char contents at 0[244]: 
Physical memory integer contents at 0[244]: 0
Physical memory char contents at 0[245]: 
Physical memory integer contents at 0[245]: 0
Physical memory char contents at 0[246]: 
Physical memory integer contents at 0[246]: 0
Physical memory char contents at 0[247]: =
Physical memory integer contents at 0[247]: 61
Physical memory char contents at 0[248]: 
Physical memory integer contents at 0[248]: 0
Physical memory char contents at 0[249]: 
Physical memory integer contents at 0[249]: 0
Physical memory char contents at 0[250]: 
Physical memory integer contents at 0[250]: 0
Physical memory char contents at 0[251]: >
Physical memory integer contents at 0[251]: 62
Physical memory char contents at 0[252]: 
Physical memory integer contents at 0[252]: 0
Physical memory char contents at 0[253]: 
Physical memory integer contents at 0[253]: 0
Physical memory char contents at 0[254]: 
Physical memory integer contents at 0[254]: 0
Physical memory char contents at 0[255]: ?
Physical memory integer contents at 0[255]: 63

这显然是错误的输出。有人能解释一下我做错了什么，以及如何做到这一点吗？

当您有：时

char c = 'a';
std::cout << c << std::endl;

输出将是

a

当c的值对应于一个非打印字符时，输出因系统而异。在您的情况下，您得到的是空白输出。

如果你想打印'a'的整数表示，你必须强制转换它。

std::cout << (int)c << std::endl;

或

int x = c;
std::cout << x << std::endl;

我希望这就是你需要的全部解释。

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