将Infix转换为前缀表示法

Convert Infix to Prefix Notation

本文关键字:表示 前缀 Infix 转换      更新时间:2023-10-16

我有一个任务:制作一个程序(C++),它将"中缀"表示法转换为"前缀",并使用自己的"堆栈和队列"实现。

但我在void main() { /*...*/ system("pause"); }的最后一个字符串或在void toPrefix(); 的最后一字符串得到:"Critical error detected c0000374""Free Heap block modified at ... after it was freed"

有人能帮我指出我的错误吗?

Source.cpp:

#include "iostream"
#include "fstream"
#include "string"
#include "Stack.h"
#include "Queue.h"
void toPrefix(const std::string& first)
{
    int length = first.length();
    char test = NULL, operand = NULL;
    char *ptr = &test, *op_ptr = &operand;
    Queue<char> List;
    std::string Output;
    Stack<char> OpStack;
    for (int i = length - 1; i >= 0; i--) List.push(first[i]); //
    while (List.getsize() != 0)
    {
        List.pop(ptr);
        if (test >= 48 && test <= 57) //is it number?
        {
            Output.insert(Output.begin(), test);
        }
        if (test == '*' || test == '/' || test == '-' || test == '+')
        {
            OpStack.push(test);
        }
        if (test == ')')
        {
            OpStack.push(test);
        }
        if (test == '(')
        {
            OpStack.pop(op_ptr);
            while (operand != ')')
            {
                Output.insert(Output.begin(), operand);
                OpStack.pop(op_ptr);
            }
        }
    }
}
void main()
{
    const std::string& first = "9-(2+2)";
    toPrefix(first);
    system("pause");
}

队列.h:

#include<iostream>
template <typename T>
class Queue
{
private:
    struct queue_element
    {
        T value;
        queue_element *next;
    };
    queue_element *first;
    queue_element *last;
    int size;
public:
    Queue()
    {
        first = new(queue_element);
        last = first;
        first->value = -1;
        first->next = 0;
        size = 0;
    }
    Queue(T x)
    {
        first = new(queue_element);
        last = first;
        first->value = x;
        first->next = 0;
        size = 1;
    }
    int getsize()
    {
        return size;
    }
    void push(T value)
    {
        if (size == 0)
        {
            size++;
            last = first;
            first->value = value;
            first->next = 0;
        }
        else
        {
            size++;
            queue_element *temp = new(queue_element);
            temp->next = 0;
            temp->value = value;
            last->next = temp;
            last = temp;
        }
    }
    void pop(T* ret)
    {
        if (size == 0)
        {
            std::cout << "Queue is empty!" << std::endl;
            return;
        }
        queue_element *temp = first;
        *ret = first->value;
        first = first->next;
        size--;
    }
    void peek(T *ret)
    {
        if (size == 0)
        {
            std::cout << "Queue is empty!" << std::endl;
            return;
        }
        *ret = first->value;
    }
};

堆栈.h

#include <iostream>
template <typename T>
class Stack
{
private:
    struct stack_element
    {
        T value;
        stack_element *next;
    };
    stack_element *first;
    stack_element *last;
    int size;
public:
    Stack()
    {
        last = new(stack_element);
        first = last;
        last->value = -1;
        last->next = first;
        size = 0;
    }
    Stack(T x)
    {
        last = new(stack_element);
        first = last;
        last->value = x;
        last->next = 0;
        size = 1;
    }
    int getsize()
    {
        return size;
    }
    void push(T value)
    {
        if (size == 0)
        {
            size++;
            last->value = value;
            last->next = first;
        }
        else
        {
            size++;
            stack_element *temp = new(stack_element);
            temp->next = last;
            temp->value = value;
            last = temp;
        }
    }
    void pop(T* ret)
    {
        if (size == 0)
        {
            std::cout << "Stack is empty!" << std::endl;
            return;
        }
        stack_element *temp = last;
        *ret = last->value;
        last = last->next;
        delete temp;
        size--;
    }
    void peek(T *ret)
    {
        if (size == 0)
        {
            std::cout << "Stack is empty!" << std::endl;
            return;
        }
        *ret = first->value;
    }
};

嗯。。。我认为问题出在你的Stack课上。

传递给toPrefix()的字符串是"9-(2+2)"

所以Stack<char> OpStack中的操作,在toPrefix()中定义的,是(如果我理解得很好的话)

  1. 使用默认(无参数)构造函数构建

  2. - 对应的push()

  3. pop()( 对应

  4. push()对应于+

  5. ) 对应的push()

好吧,让我们看看中发生了什么

1)在使用默认构造函数构造之后

我们有

1a)size == 0

1b)指向相同分配的存储器区域的firstlastfirst->nextlast->next

1c)first->value == last->value == (char)-1

2)在第一次呼叫push()(使用-)后

我们有

2a)size == 1

2b)指向相同分配的存储器区域的firstlastfirst->nextlast->next

2c)first->value == last->value == '-'

3)在第一次呼叫pop()之后

我们有

3a)size == 0

3b)指向相同DELETED内存区域的firstlastfirst->nextlast->next

3c)first->value == last->value == '-'

4)第二次调用push()(带+

4a)size递增

4b)写入(last->value = value;)删除区域

4c)在删除区域中再次写入(last->next = first;

我想这可以解释你的问题。

附言:Rambo Ramon和Sam Varshavchik提出的"使用调试器"建议是一个很好的建议(IMHO)

p.s.2:很抱歉我的英语不好