无法弄清楚出了什么问题，函数等之后的类中没有正确的变量值

Can't figure out what's wrong not a right variable value in class after functions and so on

本文关键字：变量值 之后 弄清楚 什么 函数 问题      更新时间：2023-10-16

>Heyo！我突然对突然C++编码产生了兴趣，所以我开始研究，现在我决定写一个小的基于文本的口袋妖怪游戏！但是我无法弄清楚我的代码中出了什么问题，也许我只是在做一个我不知道的新手错误？因为我什至不知道我应该在谷歌中搜索什么。这是代码：

class Charmander {
public:
int lvl=0;
int xp=0;
int str=15+3*lvl;
int agi=15+3*lvl;
int hp=30+6*lvl;
int energy=25+5*lvl;
int cen=0;
int nxp=1000;
}cha;
class Squirtle {
public:
int lvl=0;
int xp=0;
int str=15+3*lvl;
int agi=15+3*lvl;
int hp=30+6*lvl;
int energy=25+5*lvl;
int cen=0;
int nxp=1000;
}squ;
class Pikachu {
public:
int lvl;
int xp;
int str=10+2*lvl;
int agi=25+5*lvl;
int hp=25+5*lvl;
int energy=25+5*lvl;
int cen=0;
int nxp=1000;
}pik;
class Bulbasaur {
public:
int lvl=0;
int xp=0;
int str=20+4*lvl;
int agi=10+2*lvl;
int hp=35+7*lvl;
int energy=25+5*lvl;
int cen=0;
int nxp=1000;
}bul;
class CurrentPokemon {
public:
int lvl=0;
int fl=0;
int xp=0;
int str=0;
int agi=0;
int hp=0;
int energy=0;
int cen=0;
int nxp=1000;
string tag;
string name;
}curr;
int level () {
    int lvlup;
    lvlup = curr.xp/curr.nxp;
    while (lvlup >= 1) {
        lvlup = curr.xp/curr.nxp;
        if (lvlup >= 1) {
        curr.lvl++;
        curr.xp=curr.xp-curr.nxp;
        curr.nxp=curr.nxp*1.5;
        cout << "You reached level " << curr.lvl << " !" << endl;
         }
        else {
            break;
        }
    }
    }
int update () {
    if (curr.lvl >> curr.fl) {
        if (curr.name == "Pikachu") {
            pik.nxp=curr.nxp;
            pik.xp=curr.xp;
            pik.lvl=curr.lvl;
            pik.cen=curr.cen;
            curr.str=pik.str;
            curr.agi=pik.agi;
            curr.hp=pik.hp;
            curr.energy=pik.energy;
        }
    }
}

int main() {
    string a,c1,c2,c3,c4,g;
    int f;
    cout << "You are starting your journey as a pokemon master!" << endl;
    Sleep (200);
    cout << "You have to choose your companion for the advantures you will experience!" << endl;
    Sleep (200);
    tryagain:
    cout << "c for Charmander, s for Squirtle, p for Pikachu, b for Bulbasaur!" << endl;
    cin >> c1;
    if (c1 == "c") {
        a = "Charmander";
        cha.str = cha.str + 10;
        cha.agi = cha.agi + 7;
        cha.hp = cha.hp + 20;
        cha.energy = cha.hp + 20;
        cha.cen = cha.cen + 20;
        curr.str = cha.str;
        curr.agi = cha.agi;
        curr.hp = cha.hp;
        curr.energy = cha.energy;
        curr.cen = cha.cen;
        curr.tag = "Fire";
        curr.name = "Charmander";
    }
    else if (c1 == "s") {
        a = "Squirtle";
        squ.str = squ.str + 12;
        squ.agi = squ.agi + 10;
        squ.hp = squ.hp + 25;
        squ.energy = squ.energy + 20;
        squ.cen = squ.cen + 20;
        curr.str = squ.str;
        curr.agi = squ.agi;
        curr.hp = squ.hp;
        curr.energy = squ.energy;
        curr.cen = squ.cen;
        curr.tag = "Water";
        curr.name = "Squirtle";
    }
    else if (c1 == "p") {
        a = "Pikachu";
        pik.str = pik.str + 8;
        pik.agi = pik.agi + 15;
        pik.hp = pik.hp + 15;
        pik.energy = pik.energy + 20;
        pik.cen = pik.cen + 20;
        curr.str = pik.str;
        curr.agi = pik.agi;
        curr.hp = pik.hp;
        curr.energy = pik.energy;
        curr.cen = pik.cen;
        curr.tag = "Eletricity";
        curr.name = "Pikachu";
    }
    else if (c1 == "b") {
        a = "Bulbasaur";
        bul.str = bul.str + 15;
        bul.agi = bul.agi + 2;
        bul.hp = bul.hp + 30;
        bul.energy = bul.energy + 20;
        bul.cen = bul.cen + 20;
        curr.str = bul.str;
        curr.agi = bul.agi;
        curr.hp = bul.hp;
        curr.energy = bul.energy;
        curr.cen = bul.cen;
        curr.tag = "Plant";
        curr.name = "Bulbasaur";
    }
    else {
        cout << "Sorry, wrong choice, try again!" << endl;
        goto tryagain;
    }
    cout << "You have chosen " << a << " ,may you be friends forever!" << endl;
    Sleep (200);
    tryagain2:
    cout << "Would you like to pass a training course with your pokemon? (y/n)" << endl;
    cin >> c2;
    if (c2 == "y") {
        curr.xp = curr.xp + 1500;
        curr.str = curr.str + 20;
        curr.agi = curr.agi + 5;
        curr.hp = curr.hp + 5;
        curr.energy = curr.energy + 10;
        curr.cen = curr.cen - 15;
    }
    else if (c2 == "n") {
        cout << "Very well then." << endl;
    }
    level();
    update();
    cin >> f;
    if (f==1) {
        curr.xp = curr.xp + 600;
    }
    level();
        if (f==2) {
        curr.xp = curr.xp + 4600;
    }
    level();
    update();
    cout << " lvl " << curr.lvl << " xp " << curr.xp << " str " << curr.str << " agi " << curr.agi << " hp " << curr.hp << " energy " << curr.energy << " Current energy" << curr.cen << " " << curr.tag << endl;
    cout << " lvl " << pik.lvl << " xp " << pik.xp << " str " << pik.str << " agi " << pik.agi << " hp " << pik.hp << " energy " << pik.energy << " Current energy" << pik.cen << " " << endl;
    return 0;
}

每一步之后，我只对皮卡丘进行了 int 更新 （） 我想检查一切是否正确。 所以我的选择是 p -> y -> 2 我想要得到的是：str 10 -> p -> str 18 -> y -> 2 -> （此时级别为 3） -> str 24 ，但我得到的是 str 18、agi 40、hp 40、能量 45、电流能量 5、xp 1350、lvl 3（在两条线上，curr 和 pik）。

如果有人能帮助我解决这个问题，我将不胜感激！祝你有美好的一天，谢谢。

请考虑另一种设计。 也许是这样的：

class Pokemon {
protected:
  std::string name;
  int lvl;
  int xp;
  int str;
  int agi;
  int hp;
  int energy;
  int cen;
  int nxp;
public:
  Pokemon(std::string name);
  int level ();
  int update ();
};
class Charmander : public Pokemon {
public:
  Charmander ();
};
Charmander::Charmander (std::string name) 
  : Pokemon(name)
{
  name = name;
  lvl=0;
  xp=0;
  str=15+3*lvl;
  agi=15+3*lvl;
  hp=30+6*lvl;
  energy=25+5*lvl;
  cen=0;
  nxp=1000;
};
...

将常见功能分解到基类"口袋妖怪"中。

将每个类的功能添加到子类（查曼德、皮卡丘等）中。

你还应该让像"level（）"和"update（）"这样的函数成为基类的一部分。 如果行为因类而异，则使它们成为"虚拟"函数;例如，如果"Pikachu.update（）"与"Charmander.update（）"完全不同。

图书推荐：

  • 编程 -- 使用C++的原则与实践（第二版）

它并不短 - 但它很好地介绍了使用C++的C++和面向对象的设计策略。

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