未调用预期的c++虚拟函数

intended c++ virtual function not getting called

本文关键字：c++ 虚拟 函数 调用      更新时间：2023-10-16

这是我的代码

#include "stdafx.h"**
class IPlayback
{
      public:
           virtual void createRenderStream() = 0; 
};
class ICapture 
{
      public:
          virtual void createCaptureStream() = 0; 
};
class IAudioStackInterface
{
   public:
      virtual void createStream() = 0; 
};
class CAudioClientInterface : public IAudioStackInterface,
                              public ICapture,
                              public IPlayback
{
        void createCaptureStream()
        { 
            printf("n i am in createCaptureStream");
        }
        void createRenderStream()
        {
            printf("n i am in createRenderStream");
        }
        void createStream()
        {
            printf("n i am in createStream");
        }
};

typedef IAudioStackInterface* PIAudioStackInterface;
typedef ICapture* PCapture;
typedef IPlayback* PIPlayback;
typedef void* PVOID;
int main()
{
    PVOID pObj = new CAudioClientInterface();
    PIPlayback pPlayBackInterfcace = (PIPlayback) pObj;
    pPlayBackInterfcace->createRenderStream();
    return 0;
}

我应该打印createRenderstream，而我正在打印createStream？

尝试

PIPlayback pPlayBackInterfcace = (PIPlayback)(CAudioClientInterface*) pObj;

您只能强制转换为void*并返回到原始类型CAudioClientInterface*。强制转换为另一种类型是未定义的行为。

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