在另一个lambda中调用catch块中捕获的lambda会产生GCC错误

考虑以下代码:

auto lambda=[] () { std::cout << "Error occurred!" << std::endl;    };
auto lambda_2=[=/*,lambda*/] () {
    try {
        //  Do something
        std::cout << (2+2) << std::endl;
    } catch (...) {
        lambda();
        throw;
    }
};

我的期望:这个代码可以编译。

Reality (MinGW 4.8.0):

main.cpp: In lambda function:
main.cpp:27:5: error: '...' handler must be the last handler for its try block [
-fpermissive]
   } catch (...) {
     ^

如果取消注释lambda的显式副本捕获，代码将编译，但是这会发出警告:

main.cpp:20:19: warning: explicit by-copy capture of 'lambda' redundant with by-
copy capture default [enabled by default]
  auto lambda_2=[=,lambda] () {
                   ^

这是GCC的问题，还是lambda捕获的某些方面我不理解?

EDIT:以下编译:

auto lambda=[] () { std::cout << "Error occurred!" << std::endl;    };
auto lambda_2=[&] () {
    try {
        //  Do something
        std::cout << (2+2) << std::endl;
    } catch (...) {
        try {
            lambda();
        } catch (...) { }
        throw;
    }
};