同样的故事——VS VS GCC 4.6.1

Same old story - VS vs GCC 4.6.1

本文关键字：VS GCC 的故事      更新时间：2023-10-16

下面的代码在VS2010中可以正常编译，但在gcc 4.6.1中无法编译:

来自gcc的错误:

*C:…Calculator_engine_impl.h|20|error: no match for call to '(std::string{又名std::basic_string}) (__gnu_cxx::__normal_iterator>&， __gnu_cxx::__normal_iterator>&)'|*

#include "stdafx.h"

#include <iostream>
#include "Calculator_engine.h"
int main(int argc, char** argv)
{
    QString expression("1+2-3");
    auto beg = expression.begin();
    auto end = expression.end();
    while (beg != end)
    {
    qDebut() <<
     Calculator_engine<>::read_next_token_(beg,end);
    }
}
#ifndef CALCULATOR_ENGINE_H
#define CALCULATOR_ENGINE_H
#include <string>
#include <cctype>
using namespace std;
//#include "Incorrect_Expression.h"
template<class Int_T = long long>
class Calculator_engine
{
private:
    Calculator_engine();
    static Int_T expression(QString exp);
    template<class Forward_Iterator>
    static Int_T term_(Forward_Iterator& beg,Forward_Iterator& end);
public:
    template<class Forward_Iterator>
    static QString read_next_token_(Forward_Iterator& beg,Forward_Iterator& end);
public:
    static QString calculate(QString exp);
};
#include "Calculator_engine_impl.h"
#endif // CALCULATOR_ENGINE_H
#ifndef CALCULATOR_ENGINE_IMPL_H_INCLUDED
#define CALCULATOR_ENGINE_IMPL_H_INCLUDED
template<class Int_T>
class Calculator_engine;//[Forward decl]
template<class Int_T>
 template<class Forward_Iterator>
Int_T Calculator_engine<Int_T>::term_(Forward_Iterator& beg,Forward_Iterator& end)
{
    QChar token;
    Int_T result;
    switch(token)
    {
    case '*':
        break;
    case '/':
        break;
    }
}
template<class Int_T>
QString Calculator_engine<Int_T>::calculate(QString exp)
{
    Int_T result;
    auto beg = exp.begin();
    auto end = exp.end();
    while (beg != end)
    {
        QString term_ = read_next_token_(beg,end);
        QChar token = read_next_token_(beg,end);
    switch(token)
    {
    case '-':
        result -= term_(beg,end);
        break;
    case '+':
        result += term_(beg,end);
        break;
    }

    }
}
template<class Int_T>
Int_T Calculator_engine<Int_T>::expression(QString exp)
{
}

template<class Int_T>
template<class Forward_Iterator>
    QString Calculator_engine<Int_T>::read_next_token_(Forward_Iterator& beg,Forward_Iterator& end)
    {
        QString result;
        while(std::isdigit(*beg))
        {
        }
        return result;
    }
#endif // CALCULATOR_ENGINE_IMPL_H_INCLUDED

您有一个名为term_的函数和一个局部变量:

Int_T Calculator_engine<Int_T>::term_(Forward_Iterator& beg,Forward_Iterator& end)
//   ....
QString term_ = read_next_token_(beg,end);
//  ...  
result -= term_(beg,end);

GCC使用最内层的定义——在本例中是您的本地QString。然后它尝试找到一个operator()(QChar*&, QChar*&)来满足这个调用，但是失败了。显然visual studio做了一些不同的事情。我不完全确定哪个符合规范-但我怀疑GCC在这里得到了它。

当然，解决方案是局部变量和函数不要使用相同的名称。

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