ifstream打开由cin命名的文件，但从数组中提取时不打开.cin和常规字符串定义之间的任何区别

TL；DR在数组中以字符串形式存储的文件名(使用new(-ifstream不会打开它们(perror返回"No such File or directory"(。交换数组变量并调用用户来命名文件(使用cin(-ifstream打开文件。为什么？如何使数组工作？

须知

• 所有文件都存在于命名方案为run20###的文件夹中，其中
• 所有文件都命名为S20###。ABC，其中###与父目录相同，ABC可以从001-999开始。这些都是可以通过ifstream和getline打开的文本文件(没有.txt扩展名(

我正在编写一个程序，它将从多达150个文件中提取信息。我编写的早期版本让用户输入文件名(使用cin(。ifstream采用存储的名称，每次都能成功打开文件。显然，我不想键入150个文件名，所以程序将所有文件名作为字符串存储在一个数组中，供程序从中提取。然而，当它打开文件(路径正确，文件名和扩展名正确(时，我从perror得到的错误返回"No such file or directory"。如果我只是快速交换变量，使文件名来自cin，文件就会打开。为什么cin有效，而数组版本无效？有什么方法可以让数组工作吗？

在没有数组的地方，我也尝试过类似的方法。相反，在从数组中提取文件的for循环中，每次都会对文件进行命名。

以下是代码(很抱歉有标题，无法正确格式化(：

#include <iostream>
#include <array>
#include <string>
#include <ctime>
#include <cstring>
#include <fstream>
#include <sstream>
using namespace std;
int main() {
//--------------------------Initial setup----------------------------------
    cout << "Please give the full name of the folder you would like to open in the /Users/lucas/HPS/TDCData directory" << endl << endl;
    string sFolderName;
    cin >> sFolderName;
    // Create path. I have mine here but you'll have to change it to something you'll 
    // use if you want to run the code
    string sPathName = "/Users/lucas/HPS/TDCData/" + sFolderName;
//----------------Create file name array------------------------------------    
    // Get naming base from the folder name given
    string sFileBase = "S20";
    for (int i = 5; i <= sFolderName.length(); i++){
            sFileBase = sFileBase + sFolderName[i];
    }
    //Specify range since different directories have different numbers of files
    cout << "Files must be named S20###.ABC" << endl;
    cout << "Specify a range for ABC" << endl;
    int iFloor;
    int iCeiling;
    cout << "Floor: " << endl;
    cin >> iFloor;
    cout << "Ceiling: " << endl;
    cin >> iCeiling;
    // Define an array to store names and then store them
    string *aFiles;
    int iFilesSize = iCeiling - iFloor + 1;
    aFiles = new string [iFilesSize];
    cout << "Array created" << endl;
    for (int i = iFloor; i <= iCeiling; i++){
        string name = sFileBase;
        if (i < 10){
            name = name + ".00" + to_string(i);
        }
        else if (i < 100) {
            name = name + ".0" + to_string(i);
        }
        else {
            name = name + '.' + to_string(i);
        }
        aFiles[i-1] = name;
    }
//----------------Open each file in aFiles----------------------
    for (int i = 0; i < iFilesSize; i++){
        // There are two important lines of code here. The first gets sFileName from
        // aFiles. The second gets sFileName from user input using cin (this is commented out). 
        // Obviously, none of the last section of code is needed for the second line to work.
        // The first line does not work for me. The second does.
        string sFileName;
        //First
        sFileName = aFiles[i];
        //Second
        //cin >> sFileName
        string sFullPath = sPathName + "/" + sFileName;
        cout << "Searching ... " << sFullPath << endl << endl;
        //Open file
        ifstream inputFile(sFullPath);
        //Check that the file opened
        if (! inputFile.is_open()) {
        cout << "Error reading" << sFullPath << endl;
            perror("Error is: ");
            return 0;
        }
        else {
            cout << "File opened successfully..." << aFiles[i] << endl << endl;
        }
    }
    cout << "All files opened..." << endl << endl;
    return 0;
}

这里还有一个链接，指向某人可能想要运行的任何测试的一个目录的zip。感谢您的帮助！