检查Writer Function挑战

Check Writer Function challenge

本文关键字：挑战 Function Writer 检查      更新时间：2023-10-16

您好，我一直在研究这个函数，它根据数字打印支票上的字母。唯一的问题是我把它变成了一个void，我不知道如何从void-> string转换。要我说基本上是不可能的。简而言之，我如何重写它，使它返回一个字符串。

我的代码如下:

void numALet(string &can)
{
    int conNum= atoi(can.c_str());
    float conNumF= atof(can.c_str());
    //Snippet to find the Cents.
    float cen= (int)((conNumF- conNum)* 100);
    string basic[20]= { " ", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten",
                        "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"},
           diez[9]= { "Ten", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
    if(conNum< 20)
        cout<< basic[conNum]<< " and "<< (cen+ 1) << " Cents.";
    else if(conNum< 100 && conNum> 19)
    {
        int num= conNum% 100;
        if(num% 10!= 0)
            cout<< diez[num/10- 1]<< " "<< basic[num% 10]<< " and "<< (cen+ 1) << " Cents.";
        else
            cout<< diez[conNum/ 10- 1]<< " and "<< (cen+ 1)<< " Cents.";
    }
    else if(conNum> 99 && conNum< 1000)
    {
        int num1= conNum% 1000;
        cout<< basic[num1/ 100]<< " "<< "Hundred ";
        int num2= conNum% 100;
        if(conNum< 20)
            cout<< basic[num2]<< " and "<< (cen+ 1) << " Cents.";
        else if(num2< 100 && num2> 19)
        {
            if(num2% 10!= 0)
                cout<< diez[num2/ 10- 1]<< " "<< basic[num2% 10]<< " and "<< (cen+ 1) << " Cents.";
            else
                cout<< diez[num2/ 10- 1]<< " and "<< (cen+ 1) << " Cents.";
        }
    }
    else if(conNum> 999 && conNum< 10000)
    {
        cout<< basic[conNum/ 1000]<< " "<< "Thousand ";
        int num1= conNum% 1000;
        cout<< basic[num1/ 100]<< " "<< "Hundred ";
        int num2= conNum% 100;
        if(conNum< 20)
            cout<< basic[num2]<< " and "<< cen << " Cents.";
        else if(num2< 100 && num2> 19)
        {
            if(num2% 10!= 0)
                cout<< diez[num2/ 10- 1]<< " "<< basic[num2% 10]<< " and "<< (cen) << " Cents.";
            else
                cout<< diez[num2/ 10- 1];
        }
    }
}
输出:

九千九百九十九美分。

p。S:当调用cen时，它出乎意料地返回99,100，这就是我添加+ 1的原因。

谢谢你的帮助。

首先，包括lib:

#include <sstream>

然后实例化std::stringstream:

std::stringstream ss;

将cout<<替换为ss<<

最后，返回字符串流作为字符串。

return ss.str();
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