输出不显示日期是否有效

我试图输出日期是否有效。Ie 5-6-2013有效，但62-34-2013无效。当我在main中输入一个合法的日期(5,5,2013)到我的对象时，它会通过开关运行并正常工作，但是当我输入一个奇怪的日期(例如，80,52,2013)时，它只输出日期但不会说"无效日期"我遗漏了什么?(请忽略我在整个代码中所有明显的注释-它们帮助我记住我在哪里，使它更可读)谢谢!

#include <iostream>
#include <cmath>
#include <string>
#include <stdio.h>
using namespace std;
class dateType
{
    // defining the class
public:
    void setDate(int month, int day, int year);
    // Function to set the date
    int getDay() const;
    int getMonth() const;
    int getYear() const;
    void printDate() const;
    dateType(int month, int day, int year);
    dateType();
    bool isLeapYear(int yNumber);
    int dMonth;
    int dDay;
    int dYear;
private:
    int yearCalc;
    // integer to store the year, only numbers above 0 will be valid
    int monthCalc;
    // variable to store the month, January through December (1-12)
    int dayCalc;
    // variable to store the day, this varies depending on the month
    // aka 28 days in February unless it is a leap year, 31 days January, etc.
    int outputDate;
    //
};
// function definitions - setDate needs to check for validity
void dateType::setDate(int month, int day, int year)
{
    bool notValid;
    // we need to use a switch in order to run through each month.
    switch (month)
    {
        // months with 28 days - February (2), unless Leap year - test for Leap year
    case 2:
        cout << "February" << endl;
        if (isLeapYear(year))
            cout << "Leap year - 29 days" << endl;
        if (day > 29)
            notValid = true;
        break;

        // months with 31 days - April (4), June (6), September (9) November(11)
    case 4:
        cout << "April - valid, 30 days" << endl;
        break;
    case 6:
        cout << "June - valid, 30 days" << endl;
        break;
    case 9:
        cout << "September - valid, 30 days" << endl;
        break;
    case 11:
        cout << "November - valid, 30 days" << endl;
        if (day > 30)
            notValid = true;
        break;
        // months with 31 days - January (1), March (3), May (5) July(7), August (8), October (10), December (12)
        // will not incude break statement as we do not want to break
        // out of switch until the 31 day checks have been run through
    case 1:
        cout << "January - valid, 31 days" << endl;
        break;
    case 3:
        cout << "March - valid, 31 days" << endl;
        // printing out as a test to validate these months
        break;
    case 5:
        cout << "May - valid, 31 days" << endl;
        break;
    case 7:
        cout << "July - valid, 31 days" << endl;
        break;
    case 8:
        cout << "August - valid, 31 days" << endl;
        break;
    case 10:
        cout << "October - valid, 31 days" << endl;
        break;
    case 12:
        cout << "December - valid, 31 days" << endl;
        if (day >= 32)
            notValid = true;
        cout << "This is not a valid entry" << endl;
        break;
        // now break as we have checked all months ending in 31 days

    }
    dMonth = month;
    dDay = day;
    dYear = year;
}
int dateType::getDay() const
{
    return dDay;
}
int dateType::getMonth() const
{
    return dMonth;
}
int dateType::getYear() const
{
    return dYear;
}
void dateType::printDate() const
{
    cout << dMonth << "-" << dDay << "-" << dYear;
}
dateType::dateType(int month, int day, int year)
{
    setDate(month, day, year);
}
bool dateType::isLeapYear(int yNumber)
{
    if ((yNumber % 4 == 0 && yNumber % 100 != 0) || (yNumber % 400 == 0))
        return true;
    else
        return false;
}
int main()
{
    int day;
    int month;
    int year;
    dateType year1(80, 52, 2013);
    cout << "Date: ";
        year1.printDate();
        system("pause");
        return 0;

}