从'到'& # 39; time_t * & # 39;又一个错误

Invalid conversion from 'int' to 'time_t*' AND another error

本文关键字：又一个 错误 time      更新时间：2023-10-16

我得到了以下错误:

错误:从'int'到'time_t*'的转换无效

错误:初始化'time_t time(time_t*)'的参数1

我的代码是: 
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <time.h>
using namespace std;
int main()
{
char Grid[5][5];
Grid[0][0] = 'P';
Grid[0][1] = '-';
Grid[0][2] = '-';
Grid[0][3] = '-';
Grid[0][4] = '-';
Grid[1][0] = '-';
Grid[1][1] = 'T';
Grid[1][2] = '-';
Grid[1][3] = '-';
Grid[1][4] = '-';
Grid[2][0] = '-';
Grid[2][1] = '-';
Grid[2][2] = '-';
Grid[2][3] = '-';
Grid[2][4] = '-';
Grid[3][0] = '-';
Grid[3][1] = '-';
Grid[3][2] = '-';
Grid[3][3] = 'T';
Grid[3][4] = '-';
Grid[4][0] = '-';
Grid[4][1] = '-';
Grid[4][2] = '-';
Grid[4][3] = '-';
Grid[4][4] = 'X';
cout<<"P = Player (you)"<<endl<<
      "T = Trap (ouch!)"<<endl<<
      "X = Treasure (X marks the spot)"<<endl<<
      "Tell P where to go by using the commands 'right','left','up','down'."<<endl<<endl;
string command;
int x = 0;
int y = 0;
int a;
int b;
srand(time(a));
srand(time(b));
int enemy1 = rand()%4;
do
{
    cout<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl;
    cout<<Grid[0][0]<<Grid[0][1]<<Grid[0][2]<<Grid[0][3]<<Grid[0][4]<<endl<<
      Grid[1][0]<<Grid[1][1]<<Grid[1][2]<<Grid[1][3]<<Grid[1][4]<<endl<<
      Grid[2][0]<<Grid[2][1]<<Grid[2][2]<<Grid[2][3]<<Grid[2][4]<<endl<<
      Grid[3][0]<<Grid[3][1]<<Grid[3][2]<<Grid[3][3]<<Grid[3][4]<<endl<<
      Grid[4][0]<<Grid[4][1]<<Grid[4][2]<<Grid[4][3]<<Grid[4][4]<<endl;
    cout<<"Your command: ";
    cin>>command;
    cout<<endl;
    if(command=="up")
    {
        Grid[(x-1)][y] = 'P';
        x--;
        Grid[(x+1)][y] = '-';
    }
    if(command=="down")
    {
        Grid[(x+1)][y] = 'P';
        x++;
        Grid[(x-1)][y] = '-';
    }
    if(command=="right")
    {
        Grid[x][(y+1)] = 'P';
        y++;
        Grid[x][(y-1)] = '-';
    }
    if(command=="left")
    {
        Grid[x][(y-1)] = 'P';
        y--;
        Grid[x][(y+1)] = '-';
    }
    if(x==4 && y==4)
    {
        if(command=="down")
        {
            Grid[4][4] = 'P';
            cout<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl;
            cout<<Grid[0][0]<<Grid[0][1]<<Grid[0][2]<<Grid[0][3]<<Grid[0][4]<<endl<<
            Grid[1][0]<<Grid[1][1]<<Grid[1][2]<<Grid[1][3]<<Grid[1][4]<<endl<<
            Grid[2][0]<<Grid[2][1]<<Grid[2][2]<<Grid[2][3]<<Grid[2][4]<<endl<<
            Grid[3][0]<<Grid[3][1]<<Grid[3][2]<<Grid[3][3]<<Grid[3][4]<<endl<<
            Grid[4][0]<<Grid[4][1]<<Grid[4][2]<<Grid[4][3]<<Grid[4][4]<<endl;
            cout<<"You win!"<<endl;
        }
        if(command=="right")
        {
            Grid[4][4] = 'P';
            cout<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl<<endl;
            cout<<Grid[0][0]<<Grid[0][1]<<Grid[0][2]<<Grid[0][3]<<Grid[0][4]<<endl<<
            Grid[1][0]<<Grid[1][1]<<Grid[1][2]<<Grid[1][3]<<Grid[1][4]<<endl<<
            Grid[2][0]<<Grid[2][1]<<Grid[2][2]<<Grid[2][3]<<Grid[2][4]<<endl<<
            Grid[3][0]<<Grid[3][1]<<Grid[3][2]<<Grid[3][3]<<Grid[3][4]<<endl<<
            Grid[4][0]<<Grid[4][1]<<Grid[4][2]<<Grid[4][3]<<Grid[4][4]<<endl;
            cout<<"You win!"<<endl;
        }
    }
}
while(Grid[4][4] != 'P');
return 0;
}
我得到这些错误的行是第45行(和46行，但它是相同的错误)。下面的代码在第45行: 
srand(time(a));

为什么要这样使用time ?函数声明如下:

time_t time ( time_t * timer )

传递给它一个int而不是一个指向time_t的指针是一个明确的错误，编译器正确地报错。

假设您所需要的只是srand的种子，只需使用time(NULL)。如果您确实需要在参数中设置该值，则将a和b变量设置为time_t类型，并使用time(&a)。关于time的更多信息，请阅读

我几乎肯定你想调用srand(time(NULL))，只做一次。它为伪随机数生成器设置种子，并且使用实际时间是最常见的情况(每次运行应用程序时都不同，因此生成的数字序列是)。要获得实际时间，请调用time(NULL);如果你想把时间值存储在特定的time_t变量中，你可以传递它的指针而不是NULL。

这个代码:

srand(time(NULL));

和下面的代码:

time_t now;
time(&now);
srand(now);

甚至这段代码:

time_t now;
srand(time(&now));

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