我必须在c++中的类定义中包含非标准库吗?

我是c++编程的初学者，也是一般编程的初学者。我已经成功地写了一个代码来计算RSA算法的输出C，当m是十进制时相当于输出一个线性反馈移位寄存器。我把代码放在一个类中，这样我就可以多次使用它。在编译时，我得到错误通知，如:"' keyReg '没有命名类型keyReg.push_back (inpSeq[0]);"当这段代码在主类中时，它在编译时不会产生这样的错误。下面是完整的代码:

#include <iostream>
#include <algorithm>
#include <vector>
#include <math.h>
#include <boost/dynamic_bitset.hpp> 
using namespace std;
class lfsr {
 int y, xx, polyLoc, n, end, f, e, m, c, l, g;
 boost::dynamic_bitset<> inpSeq(5);
 boost::dynamic_bitset<> operSeq(5);
 boost::dynamic_bitset<> bit(5);
 vector <int> xorArray;
 vector <int> keyReg;
 polyLoc = 320;
 while(polyLoc>0)
 {
  xorArray.push_back(polyLoc%10);
  polyLoc/=10;
 }
 sort(xorArray.rbegin(), xorArray.rend());
 operSeq = inpSeq;
 keyReg.push_back(inpSeq[0]);
  int x = xorArray[0];
  do {
  for (unsigned int r = 1; r < xorArray.size(); r++)
  {
  bit[seq_end] = operSeq[x];
  y = xorArray[r];
  bit[seq_end] = bit[seq_end] ^ operSeq[y];
  }
  operSeq >>= 1;
  operSeq[seq_end]  = bit[seq_end];
  keyReg.push_back(operSeq[0]);
  turnCount ++;
 }
 while ((operSeq != inpSeq) && (turnCount < 1024));
 for ( unsigned int i = 0; i < keyReg.size(); i++)
 {
  if (keyReg[i]==1)
   {
    m = m + int(pow(2,i));
   }
n = p*q;
f = (p-1)*(q-1);
for (int k = 0; end < 1; k++)
 {
  if ( (1+k*f)%d == 0)
   {
    end = 2;
    e = (1+(k*f))/d;
   }
  }
g = int(pow(m,e));
c = g%n;
public:
 rsa (int, int, int, boost::dynamic_bitset);
 int key () { return (c); }
};
lfsr::lfsr() //Constructor
{
  y = 0;
  turnCount = 0;
  xx = 0;
  polyLoc = 0;
  n = 0;
  end = 0;
  f = 0;
  e = 0;
  m = 0;
  c = 0;
  l = 0, g = 0;
};
lfsr::rsa (int x, int y, int z, boost::dynamic_bitset <5> initSeq)
 {
  p = x;
  q = y;
  d = z;
  inpSeq = initSeq;
}
int main ()
{
lfsr public_key, private_key;
public_key.rsa (29, 41, 74, 00111);
private_key.rsa (43, 89, 73, 01011);
cout << "Public key is: " << public_key.key() << endl;
cout << "Private key is: " << private_key.key() << endl;
}