Geeksforgeeks C 程序故障排除:IEE 754 表示法为十进制

我尝试对此代码进行故障排除，但由于我是 C 语言的新手，我无法破解它。我从这篇文章中提取这个程序 Geeksforgeeks 创建： https://www.geeksforgeeks.org/program-for-conversion-of-32-bits-single-precision-ieee-754-floating-point-representation/

每次我在单独的 C++ shell 中运行此程序时，都会收到以下错误：从"无符号 int*"到"int*"的转换无效 [-允许]

有人有什么想法吗？

这是代码：

// C program to convert 
// IEEE 754 floating point representaion 
// into real value 

#include <math.h> 
#include <stdio.h> 

typedef union { 

float f; 
struct
{ 

// Order is important. 
// Here the members of the union data structure 
// use the same memory (32 bits). 
// The ordering is taken 
// from the LSB to the MSB. 

unsigned int mantissa : 23; 
unsigned int exponent : 8; 
unsigned int sign : 1; 

} raw; 
} myfloat; 

// Function to convert a binary array 
// to the corresponding integer 
unsigned int convertToInt(int* arr, int low, int high) 
{ 
unsigned f = 0, i; 
for (i = high; i >= low; i--) { 
f = f + arr[i] * pow(2, high - i); 
} 
return f; 
} 

// Driver Code 
int main() 
{ 

// Get the 32-bit floating point number 
unsigned int ieee[32] 
= { 1, 
1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 
0, 0, 0, 0, 0, 0, 0, 0, 0 }; 

myfloat var; 

// Convert the least significant 
// mantissa part (23 bits) 
// to corresponding decimal integer 
unsigned f = convertToInt(ieee, 9, 31); 

// Assign integer representation of mantissa 
var.raw.mantissa = f; 

// Convert the exponent part (8 bits) 
// to a corresponding decimal integer 
f = convertToInt(ieee, 1, 8); 

// Assign integer representation 
// of the exponent 
var.raw.exponent = f; 

// Assign sign bit 
var.raw.sign = ieee[0]; 

printf("The float value of the given"
" IEEE-754 representation is : n"); 
printf("%f", var.f); 
} 

感谢任何愿意提供帮助的人。