Read OpenCV Mat 16bit to QImage 8bit Greyscale

Read OpenCV Mat 16bit to QImage 8bit Greyscale

本文关键字:QImage 8bit Greyscale to 16bit OpenCV Mat Read      更新时间:2023-10-16

我想做什么

  1. 文件: TIFF, 2 页, 灰度, 16 位
  2. OpenCV: 2x 垫子, 灰度, 16 位 (CV_16UC1(
  3. Qt: 2x QImage, 灰度, 8 位 (Format_Greyscale8(

我想读取一个 16 位 Tiff,然后将其转换为 8 位。

读数

void ImgProc::Load_Image_2xTiff_16bit_G(Mat *Mat_A_in, Mat *Mat_B_in, string file_name)
{  
vector<Mat> vec_Mat;
vec_Mat.reserve(2);
imreadmulti(file_name, vec_Mat);
*Mat_A_in = vec_Mat[0];
*Mat_B_in = vec_Mat[1];
}

转换

void ImgProc::Convert_Mat16_2_QIm8(QImage *QIm_Out, Mat *Mat_In, double scale_factor)
{
unsigned int rows = Mat_In->rows;
unsigned int cols = Mat_In->cols;
*QIm_Out = QImage(cols, rows, QImage::Format_Grayscale8);
unsigned char* line_QIm;
if (!Mat_In->data)
return;
for(unsigned int y = 0; y < rows; y++)
{
line_QIm = QIm_Out->scanLine(y);
for(unsigned int x = 0; x < cols; x++)
{
line_QIm[x] = (unsigned char)(Mat_In->at<ushort>(y, x) * scale_factor);
}
}
}

问题

当我使用Mat_In->at<ushort>(y, x)(读取 16 位(时,它会崩溃并显示abort() has been called.如果我改用<short>,也会发生同样的情况。

当我使用Mat_In->at<uchar>(y, x)(读取 8 位(时,它可以工作,但会切断信息而不缩放。这在图像的较亮区域显示为"黑洞",可能是溢出效应。

我想我应该提到,拍摄图像的相机只使用14位深度。

我遇到了同样类型的问题。 以下代码是我用来修复这种情况的解决方案。

#include <opencv2/core.hpp>
#include <opencv2/imgproc.hpp>
#include <opencv2/highgui.hpp>
#include <QImage>
int main(void)
{
//Read the 16 bit per pixel image.
cv::Mat I = cv::imread('16BitsPerPixelImage.tiff',cv::IMREAD_ANYDEPTH|cv::IMREAD_ANYCOLOR);
//Convert from 16 bit per pixel to 8 bit per pixel using a min max normalization and store it a 8 bit per pixel.
cv::normalize(I,I,0.,255.,cv::NORM_MINMAX,CV_8U);
// Then actualy the easiest way to convert it to a QImage is to save a temporary file and open it using QT functions.
// PNG use a compression without loss algorithm.
cv::imwrite("/tmp/convert16to8.png",I);
QImage QI;
QI.load("/tmp/convert16to8.png");
return EXIT_SUCCESS;
}