C++ - 程序接收信号SIGSEGV，分段错误.In msvcrt！memcpy (） (C:\Windows\S

我回到了c ++，我正在使用code：：blocks。一切都很顺利，但我突然开始收到此错误

Program received signal SIGSEGV, Segmentation fault.In msvcrt!memcpy () (C:WindowsSystem32msvcrt.dll)'

代码编译没有错误，但是当我选择选项 1"[1] - ..."它抛出该错误。

我用谷歌搜索了一下，但我找不到任何相关的东西，或者可以帮助我解决这个问题。

我的代码是这样的：

#include <iostream>
#include <stdlib.h>
#include <string>
using namespace std;
int SeeData();
int ChangeData();
string AddTodo();
class Data {
public:
string name;
string surname;
string age;
string salary;
string todo[];
};
string dataArr[] = {"Bernardo", "Piedade", "19", "540.50"};
string todoArr[] = {"Create new functions"};
int sizeOfTodoArr = sizeof(todoArr) / sizeof(*todoArr);
int main() {
int _menuInput;
while (_menuInput != 0) {
cout << "[1] - See datan[2] - Change datan[3] - Add TODOn[0] - "
"Exitnn>>";
cin >> _menuInput;
if (_menuInput == 1) {
SeeData();
} else if (_menuInput == 2) {
ChangeData();
} else if (_menuInput == 3) {
AddTodo();
} else if (_menuInput == 0) {
system("exit");
} else {
cout << "Option not available";
system("cls");
}
}
return 0;
}
int sizeOfData = sizeof(dataArr) / sizeof(*dataArr);
int SeeData() {
Data _myData;
_myData.name = dataArr[0];
_myData.surname = dataArr[1];
_myData.age = dataArr[2];
_myData.salary = dataArr[3];
string person[sizeOfData];
for (int i = 0; i < sizeOfTodoArr; i++) {
_myData.todo[i] = todoArr[i];
}
for (int i = 0; i < sizeOfData; i++) {
person[i] = dataArr[i];
}
for (int i = 0; i < sizeOfData; i++) {
cout << "Name: " << person[0] << "nSurname: " << person[1]
<< "nAge: " << person[2] << "nSalary: " << person[3] << "nn";
cout << "Todo List: nt";
for (int j = 0; j < sizeOfTodoArr; j++) {
cout << "nt" << todoArr[j];
}
}
}
int ChangeData() {}
string AddTodo() {}

编辑：正如u/Uninitialized所说，发生错误是因为数组todo[]没有起始大小。