如何在C++中使用合成时使用"cin"进行用户输入

How to user input using "cin" while using composition in C++

本文关键字：cin 输入 用户 C++      更新时间：2023-10-16

我有三个C++类，InventoryItem、SalesPerson和Transaction。我正在使用composition在Transaction中使用InventoryItem和SalesPerson类。我想使用用户输入，而不仅仅是在构造函数中传递值，但我做不到。任何帮助都将不胜感激。下面是我的C++文件。

#include<iostream> 
#include<string> 
using namespace std; 
class InventoryItem {
private:
int stockNum; double price;
public:
InventoryItem(int, double);
void display(); };
InventoryItem::InventoryItem(int stkNum, double pr) {
stockNum = stkNum;
price = pr; 
}
void InventoryItem::display() {
cout << "Item #" << stockNum << " costs $" << price << endl;
}
//SalesPerson class
class Salesperson {
private:
int idNum;
string name; public:
Salesperson(int, string); void display();
};
Salesperson::Salesperson(int id, string lastName) {
idNum = id;
name = lastName; 
}
void Salesperson::display() {
cout << "Salesperson #" << idNum << " " << name << endl;
}
//Transaction(main class)
class Transaction {
private:
int transNum; 
InventoryItem itemSold; 
Salesperson seller;
public:
Transaction(int, int, double, int, string); 
void display();
};
Transaction::Transaction(int num, int item, double pr,
int salesId, string name) : itemSold(item, pr),
seller(salesId, name) {
transNum = num; 
}
void Transaction::display() {
cout << "Data for transaction #" << transNum << endl; itemSold.display();
seller.display();
}
int main() {
Transaction aSale(247, 782, 44.77, 512, "Richardson"); aSale.display();
return 0;
}

我将此作为回复而非评论发布，因为我的手机上没有backticks。所以你想做一些类似的事情

int main()
{
int x, y, z;
double f;
string name;
cin >> x >> y >> f >> z >> name;
Transaction(x, y, f, z, name);
return 0;
}

当然，您可以将cin行划分为每个变量一个cin和关于用户接下来必须输入的内容的cout指令。这看起来像

int main()
{
int x, y, z;
double f;
string name;
cout << "Enter x: ";
cin >> x;
cout << "Enter y: ";
cin >> y;
cout << "Enter f: ";
cin >> f;
cout << "Enter z: ";
cin >> z;
cout << "Enter name: ";
cin >> name;
Transaction(x, y, f, z, name);
return 0;
}

用要提示用户的字符串替换cout行中的字符串。

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