指向成员对象的指针 - 中断线程

Pointer to member object - Interrupt Thread

本文关键字:中断 线程 指针 成员对象      更新时间:2023-10-16

这是我昨天回答的一个问题的后续。

我正在尝试为成员函数创建一个中断线程,但我不知道这些错误是什么:

[vagrant@localhost projects]$ g++ -o test test.cpp -lpthread
test.cpp: In instantiation of ‘InterruptibleThread::InterruptibleThread(Function&&, Args&& ...)::<lambda(std::atomic_bool&, std::atomic_bool&, auto:1&&, Args&& ...)> [with auto:1 = void (MyClass::*)(int); Function = void (MyClass::*)(int); Args = {MyClass*, int}; std::atomic_bool = std::atomic<bool>]’:
/usr/local/include/c++/6.3.0/type_traits:2481:26:   required by substitution of ‘template<class _Fn, class ... _Args> static std::__result_of_success<decltype (declval<_Fn>()((declval<_Args>)()...)), std::__invoke_other> std::__result_of_other_impl::_S_test(int) [with _Fn = InterruptibleThread::InterruptibleThread(Function&&, Args&& ...) [with Function = void (MyClass::*)(int); Args = {MyClass*, int}]::<lambda(std::atomic_bool&, std::atomic_bool&, auto:1&&, MyClass*&&, int&&)>; _Args = {std::reference_wrapper<std::atomic<bool> >, std::reference_wrapper<std::atomic<bool> >, void (MyClass::*)(int), MyClass*, int}]’
/usr/local/include/c++/6.3.0/type_traits:2492:55:   required from ‘struct std::__result_of_impl<false, false, InterruptibleThread::InterruptibleThread(Function&&, Args&& ...) [with Function = void (MyClass::*)(int); Args = {MyClass*, int}]::<lambda(std::atomic_bool&, std::atomic_bool&, auto:1&&, MyClass*&&, int&&)>, std::reference_wrapper<std::atomic<bool> >, std::reference_wrapper<std::atomic<bool> >, void (MyClass::*)(int), MyClass*, int>’
/usr/local/include/c++/6.3.0/type_traits:2496:12:   required from ‘class std::result_of<InterruptibleThread::InterruptibleThread(Function&&, Args&& ...) [with Function = void (MyClass::*)(int); Args = {MyClass*, int}]::<lambda(std::atomic_bool&, std::atomic_bool&, auto:1&&, MyClass*&&, int&&)>(std::reference_wrapper<std::atomic<bool> >, std::reference_wrapper<std::atomic<bool> >, void (MyClass::*)(int), MyClass*, int)>’
/usr/local/include/c++/6.3.0/functional:1365:61:   required from ‘struct std::_Bind_simple<InterruptibleThread::InterruptibleThread(Function&&, Args&& ...) [with Function = void (MyClass::*)(int); Args = {MyClass*, int}]::<lambda(std::atomic_bool&, std::atomic_bool&, auto:1&&, MyClass*&&, int&&)>(std::reference_wrapper<std::atomic<bool> >, std::reference_wrapper<std::atomic<bool> >, void (MyClass::*)(int), MyClass*, int)>’
/usr/local/include/c++/6.3.0/thread:137:26:   required from ‘std::thread::thread(_Callable&&, _Args&& ...) [with _Callable = InterruptibleThread::InterruptibleThread(Function&&, Args&& ...) [with Function = void (MyClass::*)(int); Args = {MyClass*, int}]::<lambda(std::atomic_bool&, std::atomic_bool&, auto:1&&, MyClass*&&, int&&)>; _Args = {std::reference_wrapper<std::atomic<bool> >, std::reference_wrapper<std::atomic<bool> >, void (MyClass::*)(int), MyClass*, int}]’
test.cpp:41:33:   required from ‘InterruptibleThread::InterruptibleThread(Function&&, Args&& ...) [with Function = void (MyClass::*)(int); Args = {MyClass*, int}]’
test.cpp:111:53:   required from here
test.cpp:36:9: error: must use ‘.*’ or ‘->*’ to call pointer-to-member function in ‘fxn (...)’, e.g. ‘(... ->* fxn) (...)’
fxn( forward< Args >( args )... );

当前代码:

using namespace std;
class InterruptThreadException {};
class InterruptibleThread {
private:
static thread_local atomic_bool* stopRef;
static thread_local atomic_bool* pauseRef;
atomic_bool stopFlag{false};
atomic_bool pauseFlag{false};
thread thrd;
public:
friend void checkForInterrupt( );
template < typename Function, typename... Args >
InterruptibleThread( Function&& _fxn, Args&&... _args )
: thrd(
[]( atomic_bool& sr, atomic_bool& pr, auto&& fxn, Args&&... args ) {
stopRef = &sr;
pauseRef = &pr;
fxn( forward< Args >( args )... );
},
ref( stopFlag ),
ref( pauseFlag ),
forward< Function >( _fxn ),
forward< Args >( _args )... ) {
thrd.detach( );
}
bool stopping( ) const {
return stopFlag.load( );
}
void stop( ) {
stopFlag.store( true );
}
void pause( ) {
pauseFlag.store( true );
cout << "setting pause flag: " << pauseFlag.load( ) << endl;
}
void start( ) {
pauseFlag.store( false );
}
};
void checkForInterrupt( ) {
cout << "Pause flag: " << InterruptibleThread::pauseRef->load( ) << endl;
cout << "Stop flag: " << InterruptibleThread::stopRef->load( ) << endl;
while ( InterruptibleThread::pauseRef->load( ) ) {
cout << "Pausedn";
this_thread::sleep_for( chrono::seconds( 1 ) );
}
if ( !InterruptibleThread::stopRef->load( ) ) {
return;
}
throw InterruptThreadException( );
}
thread_local atomic_bool* InterruptibleThread::stopRef = nullptr;
thread_local atomic_bool* InterruptibleThread::pauseRef = nullptr;
void doWork( ) {
int i = 0;
try {
while ( true ) {
cout << "Checking for interrupt: " << i++ << endl;
checkForInterrupt( );
this_thread::sleep_for( chrono::seconds( 1 ) );
}
} catch ( InterruptThreadException ) {
cout << "Interruptednn";
}
}
class MyClass {
private:
int myInt;
void setInt( int i ) {
myInt = i;
}
public:
MyClass( ) : myInt( 1 ) {
}
void myWork( int i );
void doWork( );
};
void MyClass::myWork( int i ) {
setInt( i );
cout << "myInt value: " << myInt << endl;
}
void MyClass::doWork( ) {
InterruptibleThread t( &MyClass::myWork, this, 666 );
}
int main( ) {
MyClass mc;
mc.doWork( );
cout << "Press enter to exit" << endl;
getchar( );
return 0;
}

我尝试了编译器建议,之后遇到了与折叠表达式相关的错误(afaik 是 C++17,我不要使用超过 14 的任何内容(。知道如何让它工作吗?

我有一个不使用lambdas的工作版本,但我真的很好奇如何让它与原始代码一起使用。

调用指向成员函数的指针的语法与指向非成员函数或其他函子的指针不同。 由于Function在您的情况下是一个void (MyClass::*)(int),您需要使用语法(object.*fxn)(arg)(objectPtr->*fxn)(arg)来调用它。

如果您有权访问 C++17 功能,则可以使用std::invoke统一调用不同类型的可调用对象:

InterruptibleThread( Function&& _fxn, Args&&... _args )
: thrd(
[]( atomic_bool& sr, atomic_bool& pr, auto&& fxn, auto&&... args ) {
stopRef = &sr;
pauseRef = &pr;
std::invoke(std::move(fxn), std::move(args)...);
},
//...

注意:我Args&&... args更改为auto&&... argsArgs&&...因为这可能会导致问题。

如果您无法访问 C++17,您可以相当轻松地自己实现invoke

template <typename Callable,
typename... Args,
typename = std::enable_if_t<!std::is_member_function_pointer<Callable>::value>>
decltype(auto) invoke(Callable&& c, Args&&... args) {
return std::forward<Callable>(c)(std::forward<Args>(args)...);
}
template <typename T,
typename T2,
typename Ret,
typename... FuncArgs,
typename... Args,
typename = std::enable_if_t<!std::is_pointer<T2>::value>>
decltype(auto) invoke(Ret (T::*c)(FuncArgs...), T2&& t, Args&&... args) {
return (std::forward<T>(t).*c)(std::forward<Args>(args)...);
}
template <typename T,
typename T2,
typename Ret,
typename... FuncArgs,
typename... Args>
decltype(auto) invoke(Ret (T::*c)(FuncArgs...), T2* t, Args&&... args) {
return (t->*c)(std::forward<Args>(args)...);
}

这不会做std::invoke所做的一切,但它会做你需要它的一切。