错误：与'operator='不匹配(操作数类型为 'PlDrustvo' 和"PlDrustvo")|

我正在为大学编程，我坚持做一项作业。它说，"错误：与'运算符'="不匹配，但我重载了'='，所以我找不到问题。有人可以帮助我吗？谢谢

代码为：

#include <iostream>
#include <cstring>
using namespace std;
class PlDrustvo{
private:
    char *ime;
    int turi;
    int brclenovi;
public:
    PlDrustvo(){  ime = new char[1];
        strcpy(ime, " ");
        turi = 0;
        brclenovi = 0;}
    PlDrustvo(char *ime, int turi, int brclenovi){
    this->ime=new char[strlen(ime)+1];
    strcpy(this->ime,ime);
    this->turi=turi;
    this->brclenovi=brclenovi;
    }
    PlDrustvo(PlDrustvo &p){
    this->ime=new char[strlen(p.ime)+1];
    strcpy(this->ime,p.ime);
    this->turi=p.turi;
    this->brclenovi=p.brclenovi;
    }
    PlDrustvo operator+(PlDrustvo &c){
    PlDrustvo temp;
    temp.brclenovi=this->brclenovi+ c.brclenovi;
    if(this->brclenovi>c.brclenovi){
        temp.ime=new char[strlen(this->ime)+1];
        strcpy(temp.ime,this->ime);
        temp.turi=this->turi;
        }
    else
    {
     temp.ime=new char[strlen(c.ime)+1];
     strcpy(temp.ime,c.ime);
     temp.turi=c.turi;
    }
    return temp;
    }
    PlDrustvo& operator=(PlDrustvo &p){
    if(this!=&p)
    {
        delete [] this->ime;
        this->ime=new char[strlen(p.ime)+1];
    strcpy(this->ime,p.ime);
    this->turi=p.turi;
    this->brclenovi=p.brclenovi;
    }
    return *this;
    }
bool operator>(PlDrustvo &p){
return this->brclenovi>p.brclenovi;
}
bool operator<(PlDrustvo &p){
return brclenovi<p.brclenovi;
}
friend ostream& operator<<(ostream &alek, PlDrustvo &p){
alek<<"Ime: "<<p.ime<<" Turi: "<<p.turi<<" Clenovi: "<<p.brclenovi<<endl;
return alek;
}
friend void najmnoguClenovi(PlDrustvo*, int);
};
void najmnoguClenovi(PlDrustvo *pl,int n){
int i_max = 0;
    for(int i=0; i<n; i++)
        if(pl[i].brclenovi > pl[i_max].brclenovi)
            i_max = i;
    cout << "Najmnogu clenovi ima planinarskoto drustvo: " << pl[i_max];
}
int main()
{
    PlDrustvo drustva[3];
    PlDrustvo pl;
    for (int i=0;i<3;i++)
    {
        char ime[100];
        int brTuri;
        int brClenovi;
        cin>>ime;
        cin>>brTuri;
        cin>>brClenovi;
        PlDrustvo p(ime,brTuri,brClenovi);
        drustva[i] = p;
    }
    pl = drustva[0] + drustva[1]; //HERE IS THE ERROR
    cout<<pl;
    najmnoguClenovi(drustva, 3);
    return 0;
}