如何将 cin 传递给函数

How to pass cin to a function?

本文关键字:函数 cin      更新时间:2023-10-16

我正在学习C++中不同的流状态标志/函数,例如good((,goodbit,bad((,badbit等。在使用 std::cin 进行测试时,我无法将 cin 作为参数传递给函数(编译器显示很多错误(

#include <iostream>
#include <sstream>
 void print_state (const std::istream& stream) {
    std::cout << " good()=" << stream.good();
    std::cout << " eof()=" << stream.eof();
    std::cout << " fail()=" << stream.fail();
    std::cout << " bad()=" << stream.bad();
} 
int main() {
    std::cin.clear (std::ios::goodbit);
    std::cout << "goodbit: " << print_state(std::cin) << std::endl;
    std::cin.clear (std::ios::eofbit);
    std::cout << "eofbit: " << print_state(std::cin) << std::endl;
    std::cin.clear (std::ios::failbit);
    std::cout << "failbit: " << print_state(std::cin) << std::endl;
    std::cin.clear (std::ios::badbit);
    std::cout << "badbit: " << print_state(std::cin) << std::endl;
    return 0;
}

期望输出:

goodbit: good()=1 eof()=0 fail()=0 bad()=0
 eofbit: good()=0 eof()=1 fail()=0 bad()=0
failbit: good()=0 eof()=0 fail()=1 bad()=0
 badbit: good()=0 eof()=0 fail()=1 bad()=1

我知道我可以直接使用 cin 调用函数,例如 std::cin.good() ,但我想知道如何将 cin 作为参数传递给函数。

编辑:我在编译过程中遇到很多错误。举个例子:

F:cpp_programmingstream_states.cpp: In function 'int main()':
F:cpp_programmingstream_states.cpp:13:27: error: no match for 'operator<<' (operand types are 'std::basic_ostream<char>' and 'void')
  std::cout << "goodbit: " << print_state(std::cin) << std::endl;
  ~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~

由于 print_state 不返回值,因此不能与插入运算符 << 一起使用。纠正此问题的最简单方法是自行调用print_state

print_state(std::cin);

更正后的代码如下:

#include <iostream>
#include <sstream>
 void print_state (const std::istream& stream) {
    std::cout << " good()=" << stream.good();
    std::cout << " eof()=" << stream.eof();
    std::cout << " fail()=" << stream.fail();
    std::cout << " bad()=" << stream.bad();
} 
int main() {
    std::cin.clear (std::ios::goodbit);
    std::cout << "goodbit: "; print_state(std::cin); std::cout << std::endl;
    std::cin.clear (std::ios::eofbit);
    std::cout << "eofbit: "; print_state(std::cin); std::cout << std::endl;
    std::cin.clear (std::ios::failbit);
    std::cout << "failbit: "; print_state(std::cin); std::cout<< std::endl;
    std::cin.clear (std::ios::badbit);
    std::cout << "badbit: "; print_state(std::cin); std::cout << std::endl;
    return 0;
}

回答我自己的问题

cin可以作为函数参数传递给函数,例如:

functionName(std::cin);