C 程序处理两个文件，而不是一个文件

因此，对于分配，我必须读取文件并计数其行，单词和字符。问题是我编写的程序将读取两个文件，但不是一个文件，该程序将文本文件视为无法打开并将其发送到其他语句的内容。我觉得也许我把东西弄乱了，但是我觉得很奇怪，它可以读两个文件而不是一个文件。代码：

#include <iostream>
#include <fstream> // for file-access
#include <iomanip>
using namespace std;
int main(int argc, char* argv[])
{
    if (argc > 1){}
    else
    {
        cout << "File anInvalidFileName is not found" << endl;
        return -1;
    }
    ifstream infile(argv[1]);
    if (infile.is_open() && infile.good())
    {
        string line1 = "";
        int countline1 = 0;
        int charcount1 = 0;
        char space1;
        int countspace1 = 0;
        int empty1 = 0;
        while (getline(infile, line1))
        {
            if (line1.empty())
            {
                empty1++;
            }
            countline1++;
            charcount1 += line1.length() + 1;
            for (int i = 0; i < line1.length(); i++)
            {
                if (line1[i] == ' ')
                {
                    countspace1++;
                }
            }
        }
        countspace1 = (countline1 - empty1) + countspace1;
        ifstream infile(argv[2]); //open the file
        if (infile.is_open() && infile.good())
        {
            string line2 = "";
            int countline2 = 0;
            int charcount2 = 0;
            char space2;
            int countspace2 = 0;
            int empty2 = 0;
            while (getline(infile, line2))
            {
                if (line2.empty())
                {
                    empty2++;
                }
                countline2++;
                charcount2 += line2.length() + 1;
                for (int i = 0; i < line2.length(); i++)
                {
                    if (line2[i] == ' ')
                    {
                        countspace2++;
                    }
                }
            }
            countspace2 = (countline2 - empty2) + countspace2;
            int countline = 0;
            int countspace = 0;
            int charcount = 0;
            countline = countline1 + countline2;
            countspace = countspace1 + countspace2;
            charcount = charcount1 + charcount2;
            cout << setw(12) << countline1;
            cout << setw(12) << countspace1;
            cout << setw(12) << charcount1 << " ";
            cout << argv[1] << endl;
            cout << setw(12) << countline2;
            cout << setw(12) << countspace2;
            cout << setw(12) << charcount2 << " ";
            cout << argv[2] << endl;
            cout << setw(12) << countline;
            cout << setw(12) << countspace;
            cout << setw(12) << charcount << " ";
            cout << "totals" << endl;
        }
        else
        {
            cout << "error" << endl;
        }
        return 0;
    }
    else
    {
        cout << "error" << endl;
    }
}

我添加了错误输出，只是为了查看一个文件失败时将其发送到何处。它确实转到了其他方面，因为当我运行程序时，它会打印出错误。至于输入，教授提供了在运行程序时自动运行的测试用例。我觉得这可能是一个简单的错误，也许我想念ARGV的工作原理，但是欢迎任何帮助。如果需要更多信息，我将尝试添加它。