读取字符列表并存储在数组中

C++：

std::vector<int> v;
std::string s;
int i;
std::getline( std::cin, s);         // read full line with whitespaces
std::istringstream iss( s);         // prepare to process the line
while( iss >> i) v.push_back( i);   // read into i and push into vector if 
                                    // operator>> was successful

C：

int array[ 10];
int i = 0, retval;
while( i < 10 && ( retval = scanf( "%d", &array[ i++])) == 1) ; 
if( i == 10) {
    // array full
}
if( retval == 0) {
    // read value not an integer. matching failure
}
if( retval == EOF) {
    // end of file reached or a read error occurred
}

您正在逐个字符进行决定。因此，您将只存储单个数字或忽略这些数字。

你可以像这样存储整个数字（扩展你的代码）：

bool currentNumberStarted = false;
int currentNumber = 0;
int idx = 0;
while ((in=getchar()) != '0')// you probably want '' instead of '0'
{
    if (in == ' ')
    {
                    if (currentNumberStarted)
                    {
                        input[idx]=currentNumber;
                        idx++;
                        currentNumberStarted = false;
                    }
        printf("spacen ");
        continue;
    }
    else
    {
        printf("assigningn ");
                    currentNumberStarted = true;
                    currentNumber *= 10;
        currentNumber += in;
    }
}
printf("Out of Loop");

首先，我非常怀疑while循环是否会结束，即使您对''进行了此操作，因为您使用的是char变量来存储输入。不是字符串，只有字符串在末尾使用''，我们如何从键盘输入"\0"。。？？？。即使你想把它保持为'0'，你也必须输入0作为最后一个数字来结束循环（我认为你不想这样做。）

因此，解决方案是：-

输入数字后，您将按ENTER键，这将生成一个换行符"\n"，因此您必须检查换行符（'n'），并且当您使用getchar（）函数时，它将在输入结束时返回EOF（-1），因此检查它也很重要。因此，您必须在while循环中同时检查'\n'和EOF。最后，您还应该检查存储数字的数组索引号（应该小于1）。

我在评论中努力让你理解这个节目。

int main()
{
  int i=0;
  int input[10]={0}; //here only 10 integers can be entered(hence i should be i<10)
  int in;     //To store input character
  int num=0;  //To store number which is converted from character.
  int new=1;  //To check if new number is started 0=false 1=True.
  int count=0;//This is just to know how many numbers entered,also used to print numbers at end.
  while ((in=getchar()) != 'n' && (in!=EOF) && i<10)//should check for both 'n' and EOF and array index also
  {
      if (in == ' ')
      {
         printf("spacen ");
         if(new==0) //if new Number is not started yet.
         {
            new=1;  //Start of a New number.(a number entered after space)
            i++;  //As new number is started it should be stored in new array index.
         }
         continue; //if space is entered just go to begining
      }
      else
      {
         printf("assigningn ");
         num=in-48;  //converts a character to number (ex:- converts '3' to 3)
         input[i]=(input[i]*10)+num;  //storing the number..This is important do a paper work to understand this step.
         new=0;  //still in same number(we are still processing same number)
      }
  }
  printf("Out of Loop n");
  count=i+1;  //This gives correct count of numbers entered
  for(i=0;i<count;i++)  //to print numbers.
     printf("%d ",input[i]);
return 0;
}

输出：-

E：>example.exe

78 2 65 998 1

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78 2 65 998 1