0%2 coming out to be 1
0%2 coming out to be 1
我遇到了一个奇怪的问题。这是我正在使用输入和输出的代码的链接。我遇到问题的片段发布在这里
printf("before modulo r= %d ,ans =%dn",r/b,ans );
ans=(ans)%2;
printf("after modulo r = %d ,ans =%dn",r,ans);
可以看到，在执行第 24 行之前的第二次迭代中，ans = 0，之后它变为 1 而不是保持 0 为 0%2=0 。我真的无法理解这个问题
你的第一次打印不会打印 ans，因为你的 b 是一个长整型，所以 r/b 是一个长整型，它有 64 位，你的第一次打印会将前 32 位打印为 r，接下来的 32 位打印为 ans。你的 ans 从来都不是 0。
下次，请发布您的代码而不是链接它。
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