用libxml2解析XML文件的最快方法

Fastest way to parse a XML file with libxml2?

本文关键字：方法 文件 libxml2 解析 XML      更新时间：2023-10-16

嗨，有没有" 更快"用libxml2解析XML文件的方法？现在，我按照C 代码这样做：

void parse_element_names(xmlNode * a_node, int *calls)
{
    xmlNode *cur_node = NULL;
    for (cur_node = a_node; cur_node; cur_node = cur_node->next) {
      (*calls)++;
      if(xmlStrEqual(xmlCharStrdup("to"),cur_node->name)){
        //printf("node type: <%d>, name <%s>, content: <%s> n", cur_node->children->type, cur_node->children->name, cur_node->children->content);
        //do something with the content
        parse_element_names(cur_node->children->children,calls);
        }
      else if(xmlStrEqual(xmlCharStrdup("from"),cur_node->name)) {
        //printf("node type: <%d>, name <%s>, content: <%s> n", cur_node->children->type, cur_node->children->name, cur_node->children->content);
        //do something with the content
        parse_element_names(cur_node->children->children,calls);
        }
      else if(xmlStrEqual(xmlCharStrdup("note"),cur_node->name)) {
        //printf("node type: <%d>, name <%s>, content: <%s> n", cur_node->children->type, cur_node->children->name, cur_node->children->content);
        //do something with the content
        parse_element_names(cur_node->children->children,calls);
        }
        .
        .
        .
        //about 100 more node names comming
      else{
        parse_element_names(cur_node->children,calls);
      }
    }
}
int main(int argc, char **argv)
{ 
    xmlDoc *doc = NULL;
    xmlNode *root_element = NULL;
    if (argc != 2)
        return(1);
    /*parse the file and get the DOM */
    doc = xmlReadFile(argv[1], NULL, XML_PARSE_NOBLANKS);
    if (doc == NULL) {
        printf("error: could not parse file %sn", argv[1]);
    }
    int calls = 0;
    /*Get the root element node */
    root_element = xmlDocGetRootElement(doc);
    parse_element_names(root_element,&calls);
    /*free the document */
    xmlFreeDoc(doc);
    xmlCleanupParser();
    return 0;
}

真的是最快的方法吗？还是有更好/更快的解决方案，您可以建议我？

谢谢

xmlReadFile等。基于Libxml2的SAX Parser接口（实际上是SAX2接口），因此，如果您不需要生成的xmlDoc。

如果您必须区分示例中的许多不同元素名称，则最快的方法通常是为每种类型的节点创建单独的功能，并使用哈希表来查找这些函数。

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