如何将目录中所有具有完整路径的文件传递到execv中的参数数组

How can i pass all files with full path in a directory to the argument array in execv?

本文关键字：文件 数组 参数 路径 execv      更新时间：2023-10-16

我正在尝试读取给定目录中的所有文件（图片），并将其传递给execv。我想启动帧缓冲区图像查看器（fbi）。

目前，当我从图片所在的目录启动它时，它就可以工作了。我如何操作矢量，使其不仅包含文件名，还包含路径+文件名？

int startSlideshow (char* pathtoFBI) {
pid_t fbiPid;
fbiPid = fork();
if (fbiPid == 0) {
    /* this is the child process */
    DIR *pictureDirectory;
    struct dirent *dir;
    int i = 0;
    vector<char*> argVector;
    char pDirectory[] = "/home/pi/bilder/";
    argVector.push_back(pathtoFBI);         /* first Argument is Program name */
    pictureDirectory = opendir(pDirectory);
    if (pictureDirectory){
        while ((dir = readdir(pictureDirectory)) != NULL) {
            i++;
            if (i > 2) {            /* first element is "." second is ".." */
                argVector.push_back(dir->d_name);
            }
        }
        //i -= 2;
    } else ERREXIT("reading picture directory");
    closedir(pictureDirectory);
    argVector.push_back(NULL);
    char** fbiArgv = &argVector[0];
    execvp(pathtoFBI, fbiArgv);         /* pid is taken over by fbi */
    _exit(EXIT_FAILURE);
}

给定您的代码，您只需要为每个文件名预先添加pDirectory：

--- c1.cc       2013-02-04 02:35:47.000000000 +0400
+++ c2.cc       2013-02-04 02:39:03.000000000 +0400
@@ -8,7 +8,7 @@
     DIR *pictureDirectory;
     struct dirent *dir;
     int i = 0;
-    vector<char*> argVector;
+    vector<char*> argVector; vector<string> fpVector;
     char pDirectory[] = "/home/pi/bilder/";
     argVector.push_back(pathtoFBI);         /* first Argument is Program name */
     pictureDirectory = opendir(pDirectory);
@@ -16,7 +16,8 @@
         while ((dir = readdir(pictureDirectory)) != NULL) {
             i++;
             if (i > 2) {            /* first element is "." second is ".." */
-                argVector.push_back(dir->d_name);
+                fpVector.push_back(string(pDirectory) + dir->d_name);
+                argVector.push_back((char*) fpVector.back().c_str());
             }
         }
         //i -= 2;

更普遍地说，Boost文件系统是绝对的和规范的。

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