如何在 c++ 中使用 "int promptYN(string reply)" 结束刽子手游戏

在我的刽子手游戏中，我无法结束游戏。使用我定义的头文件...

#define PLAY 1 #define STOP 0 #define ERROR -1

。然后我定义了函数

int promptYN(string reply)
{
    reply = strToUpper(reply);
    if (reply == "YES", "OK", "SURE", "Y")
        return PLAY;
    else if (reply == "NO", "QUIT", "STOP", "TERMINATE", "N", "Q")
        return STOP;
    else
        return ERROR;
}

。现在，无论用户键入什么，该函数都已在main中调用，即使我以"NO"，"QUIT"，"STOP"，"TERMINATE"，"N"，"Q"响应。

这是我用来尝试玩游戏的while循环，我只需要帮助弄清楚用户何时响应"Y"，然后游戏播放，"N"然后游戏停止，或ERROR和游戏重置为再次提问。谢谢！

    cout << "Do you want to play hangman? (y or n): ";
    cin >> userReply;
    gameStatus = promptYN(userReply);
    while (gameStatus != STOP)
    {
        if (gameStatus == PLAY)
        {
            chances = 0;
            cout << "Let's Playnn";
            guessWord = getNextWord();                  // Function call (randword.h)
            guessWord = strToUpper(guessWord);          // Function call (MyFuncts.h)
            cout << "nWord to Guess: " << guessWord << endl;
            cout << endl << h1;

            while (wrong != 6)                          // Function to find out which hangman board to print to user
            {
                cout << "nEnter a letter to guess: ";
                cin >> gLetter;
                gLetter = toupper(gLetter);
                cout << "You entered: " << gLetter << endl << endl;
                cout << gLetter << " is NOT in the word to guess.";
                wrong++;
                if (wrong == 0)
                    cout << endl << h1 << endl;
                if (wrong == 1)
                    cout << endl << h2 << endl;
                if (wrong == 2)
                    cout << endl << h3 << endl;
                if (wrong == 3)
                    cout << endl << h4 << endl;
                if (wrong == 4)
                    cout << endl << h5 << endl;
                if (wrong == 5)
                    cout << endl << h6 << endl;
                if (wrong == 6)
                    cout << endl << h7 << endl;
            }
        }
        else if (gameStatus == STOP)
        {
            cout << "Goodbyen";
        }
        else
        {
            cout << "Error - please enter (y or n)n";
        }
        cout << "Do you want to play hangman? (y or n): ";
        cin >> userReply;
        gameStatus = promptYN(userReply);
    }