这个 c++ 程序中缺少什么?打印计算

What is missing in this c++ program? printing calculations

本文关键字：什么 打印 计算 c++ 程序 这个      更新时间：2023-10-16
#include <iostream>
#include <iomanip>
using namespace std;
int main () // print to console: 3.0*5.0=15.00
{
double a;
double b;
a =(3.0);
b =(5.0);
cout << "  " << fixed << setprecision (1) << a << "n" << endl;
cout << "* " << b << "n" << endl;
cout << "------" << endl;
cout << fixed << setprecision (2) << a*b << "n" << endl;
return 0;
}
int calculate (int a, int b, int c) // print to console: (7.1*8.3)-2.2=56.73
{
double a;
    double b;
    double c;
    a = (7.1);
    b = (8.3);
    c = (2.2);
    cout << "  " << fixed << setprecision (1) << a << "n" << endl;
    cout << "* " << b << "n" << endl;
    cout << "- " << c << "n" << endl;
    cout << "------" << endl;
    cout << setprecision(2) << (a*b)-c << "n" << endl;
}
int calculation (int a, int b, int c) // print to console: 3.2/(6.1*5.0)=0.10
{
double a;
double b;
double c;
a=(3.2);
b=(6.1);
c=(5.0);
cout << "  " << fixed << setprecision (1) << a << "n" << endl;
    cout << " /(6.1*5.0)" << endl; //how can I use variables instead of using quotes?
cout << "------" << endl;
cout << setprecision(2) << a/(b*c) << "n" << endl;
system("PAUSE");
return 0;
}

我使用了重复的布局，我希望垂直打印 3 个函数，以便小数点都对齐。我似乎无法在没有错误的情况下进行打印，并且认为我对错误输出的理解不足以进行必要的更改。我不知道我是否正确地重新定义了变量，或者我是否正确地将它们放在一起（使用 {}）。

感谢任何可以帮助我解决这个问题的人。

这是输出：

(7): error C2082: redefinition of formal parameter 'a'
(8): error C2082: redefinition of formal parameter 'b'
(9): warning C4244: '=' : conversion from 'double' to 'int', possible loss of data
(10): warning C4244: '=' : conversion from 'double' to 'int', possible loss of data
(21): error C2082: redefinition of formal parameter 'a'
(22): error C2082: redefinition of formal parameter 'b'
(23): error C2082: redefinition of formal parameter 'c'
(24): warning C4244: '=' : conversion from 'double' to 'int', possible loss of data
(25): warning C4244: '=' : conversion from 'double' to 'int', possible loss of data
(26): warning C4244: '=' : conversion from 'double' to 'int', possible loss of data
(34): error C2601: 'calculation' : local function definitions are illegal
(20): this line contains a '{' which has not yet been matched
(51): fatal error C1075: end of file found before the left brace '{'

我将如何修复这些错误？

您错过了以下之后的右大括号：

int calculate (int a, int b, int c) // print to console: (7.1*8.3)-2.2=56.73
{
    ....
    ....
    cout << setprecision(2) << (a*b)-c << "n" << endl;
}

^^^^

由于两个函数中具有相同的命名符号，因此缺少大括号会导致符号名称被多次使用，从而违反一个定义规则，从而导致重定义错误。

另外，请注意@Ed.S在评论中正确指出的内容。

另外，请注意类型转换的警告，您可能需要在程序逻辑中考虑这一点。

首先：

int

main（int， int） - 非常非标准的程序入口点

下一个 ：

int main (int a, int b) // print to console: 3.0*5.0=15.00
{
double a;
double b;

您正在重新定义形式参数 a 和 b

就是这样，这就是编译器所说的：

(7): error C2082: redefinition of formal parameter 'a'
(8): error C2082: redefinition of formal parameter 'b'

.

int calculate (int a, int b, int c) // print to console: (7.1*8.3)-2.2=56.73
{
double a;
    double b;
    double c;

您具有相同的局部变量和正式参数名称，我认为这不是您所期望的。

最后一个：

计算函数末尾缺少右括号"}"。

#include <iostream>
#include <iomanip>
using namespace std;
int main () // print to console: 3.0*5.0=15.00
{
double a;
double b;
a =(3.0);
b =(5.0);
cout << "  " << fixed << setprecision (1) << a << "n" << endl;
cout << "* " << b << "n" << endl;
cout << "------" << endl;
cout << fixed << setprecision (2) << a*b << "n" << endl;
return 0;
}
int calculate () // print to console: (7.1*8.3)-2.2=56.73
{
    double a;
    double b;
    double c;
    a = (7.1);
    b = (8.3);
    c = (2.2);
    cout << "  " << fixed << setprecision (1) << a << "n" << endl;
    cout << "* " << b << "n" << endl;
    cout << "- " << c << "n" << endl;
    cout << "------" << endl;
    cout << setprecision(2) << (a*b)-c << "n" << endl;
}
int calculation () // print to console: 3.2/(6.1*5.0)=0.10
{
    double a;
    double b;
    double c;
    a=(3.2);
    b=(6.1);
    c=(5.0);
    cout << "  " << fixed << setprecision (1) << a << "n" << endl;
    cout << b << "*" << c << endl; //how can I use variables instead of using quotes?
    cout << "------" << endl;
    cout << setprecision(2) << a/(b*c) << "n" << endl;
    system("PAUSE");
    return 0;
}

您在int calculate函数之后缺少}。虽然不相关，但您也不必多次拨打fixed和setprecision。

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