分析示例文本文件并将其拆分

我试图浏览一个包含汇编指令的简单文本文件，它看起来像这个

TOP   NOP
VAL   INT 0
TAN   LA 2,1

这只是一个小例子，所以我可以向你展示它是如何工作的。基本上，我将第一个标签放在标签中，然后第二个标签是NOP、INT和LA，并将它们放在操作码中。

之后，我将采用第一个参数(0和2)，并将它们放置在arg1中。然而，这就是我的问题所在。对于我现有的代码，当我将参数放入字符串时，我得到的输出是这样的

TOP
0
2

很明显，我只想让最后两个成为唯一的，但我该如何做到这一点，让TOP不会在我的第一次争论中陷入困境？

#include <string>
#include <iostream>
#include <cstdlib>
#include <string.h>
#include <fstream>
#include <stdio.h>
using namespace std;
int main(int argc, char *argv[])
{
// If no extra file is provided then exit the program with error message
if (argc <= 1)
{
cout << "Correct Usage: " << argv[0] << " <Filename>" << endl;
exit (1);
}
// Array to hold the registers and initialize them all to zero
int registers [] = {0,0,0,0,0,0,0,0};
string memory [16000];
string Symtablelab[1000];
int Symtablepos[1000];
string line;
string label;
string opcode;
string arg1;
string arg2;
// Open the file that was input on the command line
ifstream myFile;
myFile.open(argv[1]);
if (!myFile.is_open())
{
cerr << "Cannot open the file." << endl;
}
int counter = 0;
int i = 0;
int j = 0;
while (getline(myFile, line, 'n'))
{
if (line[0] == '#')
{
continue;
}
if (line.length() == 0)
{
continue;
}
if (line[0] != 't' && line[0] != ' ')
{
string delimeters = "t ";
int current;
int next = -1;
current = next + 1;
next = line.find_first_of( delimeters, current);
label = line.substr( current, next - current );
Symtablelab[i] = label;
current = next + 1;
next = line.find_first_of(delimeters, current);
opcode = line.substr(current, next - current);
if (opcode != "WORDS" && opcode != "INT")
{
counter += 3;
}
if (opcode == "INT")
{
counter++;
}
delimeters = ", nt";
current = next + 1;
next = line.find_first_of(delimeters, current);
arg1 = line.substr(current, next-current);
cout << arg1<<endl;
i++;
}
}