C++11可变模板函数存储

C++11 variadic template function storage

本文关键字:函数 存储 C++11      更新时间:2023-10-16

我目前正在将回调系统重新设计为C++11可变模板。基本上,我要做的是存储一个带有返回值和任意数量参数的函数。

之后,应该调用此函数,从boost::archive加载参数,并将返回值写回另一个存档。

#include <string>
#include <map>
#include <iostream>
#include <boost/archive/binary_iarchive.hpp>
#include <boost/archive/binary_oarchive.hpp>
using iarchive = boost::archive::binary_iarchive;
using oarchive = boost::archive::binary_oarchive;
using namespace std;
template<class Interface>
class RFCProvider : public Interface {
    class FuncStore {
    public:
        virtual ~FuncStore() {}
        virtual void call(iarchive& in, oarchive& out) = 0;
    protected:
        template <class T> T read(iarchive& in) { T a; in >> a; return a; }
    };

    template<class Return, class... Args>
    class FuncStoreRetN : public FuncStore {
        public:
            typedef Return(Interface::*Function)(Args... args);
            typedef Return ReturnType;
            static const int ArgCount = sizeof...(Args);
        private:
            struct pass {
                Return res;
                pass(Interface* me, Function func, Args... args) { res = (me->*func)(args...); }
            };
            Interface* mMe;
            Function mFunc;
        public:
            FuncStoreRetN(Interface* me, Function func) : mMe(me), mFunc(func) {}
            void call(iarchive& in, oarchive& out) {
                pass c{mMe, mFunc, read<Args>(in)...};
                out << c.res;
            }
    };

    map<string, FuncStore*> functionStore;
public:
    template<class Return, class... Args>
    void registerFunction(const string& name, Return(Interface::*func)(Args...)) {
        functionStore[name] = new FuncStoreRetN<Return, Args...>(this, func);
    }
};

class TestClass {
public:
    bool foo(int x) { return x == 0; }
};

int main() {
    RFCProvider<TestClass> p;
    p.registerFunction("foo", &TestClass::foo);
    return 0;
}

根据我的理解,pass c{mMe, mFunc, read<Args>(in)...};应该扩展到pass c{mMe, mFunc, read<int>(in), read<string>(in), ...};,对吗?

但是我不能用g++编译(Ubuntu 4.8.2-19ubuntu1)4.8.2

error: expected primary-expression before ‘>’ token
     pass c{mMe, mFunc, read<Args>(in)...};
                                 ^

有什么建议吗?

编辑:添加MCVE

更换

pass c{mMe, mFunc, read<Args>(in)...};

带有

pass c{mMe, mFunc, FuncStore::template read<Args>(in)...};

由于所有这些都发生在类模板中的嵌套类(和类模板)中,因此应用依赖名称查找,并且必须为编译器添加常见的说明。