重载按位运算符 XOR

当我完成Money Class项目的工作时，我只剩下一条指令，即使用按位运算符^将两个Money对象四舍五入。

在我的头文件中，我有：

#ifndef MONEY_H
#define MONEY_H
#include <iostream>
using namespace std;
class Money{
    public:
        Money(int dollars, int cents);
        Money(int dollars);
        Money();
        int getDollars() const {return dollars;};
        int getCents() const {return cents;};
        void setDollarsAndCents(int dollars, int cents);
        double getAmount() const {return dollars + cents / 100.0    ;};
        void setAmount(double amount);
        //Define bit wise operator
        friend Money operator^(const Money& firstAmount, const Money& secondAmount);
        //Define the input and output operator
        friend istream& operator>>(istream& inputStream, const Money& money);
        friend ostream& operator<<(ostream& outStream, const Money& money);
    private:
        int dollars, cents;
        double amount;
};
const Money LOONIE = Money(1 , 0);
const Money TOONIE = Money(2 , 0);
const Money QUARTER = Money(0 , 25);
const Money DIME = Money(0 , 10);
const Money NICKEL = Money(0 , 5);
#endif

在我的实现文件中：

    #include "Money.h"
// Construct a money object with dollars and cents
Money::Money(int newDollars, int newCents)
{
    dollars = newDollars;
    cents = newCents;
    amount = dollars + cents/100.0;
}
// Construct a money object with JUST the dollars
Money::Money(int newDollars)
{
    dollars = newDollars;
    cents = 0;
    amount = dollars + cents;
}
// Construct a money object with no arguments (default amount = 0)
Money::Money()
{
    amount = 0.0;
}
// Set dollars and cents
void Money::setDollarsAndCents(int newDollars, int newCents)
{
    dollars = newDollars;
    cents = newCents;
    amount = dollars + cents/100.0;
}
// Set monetary amount
void Money::setAmount(double newAmount)
{
    amount = newAmount;
}
// Round up first Money object to the nearest second Money object
Money operator^(const Money& firstAmount, const Money& secondAmount)
{
    int finalDollars = firstAmount.dollars + secondAmount.dollars); 
    firstAmount.cents += secondAmount.cents/2; 
    return Money(finalDollars, ((firstAmount.cents/secondAmount.cents)*secondAmount.cents));
}
// Define the input operator
istream& operator>>(istream& inputStream, const Money& money)
{
    inputStream >> money.dollars >> money.cents;
    return inputStream;
}
// Define the output operator
ostream& operator<<(ostream& outputStream, const Money& money)
{
    outputStream << money.dollars << "." << money.cents;
   return outputStream;
}

注意：我认为我不需要做int finalDollars因为我没有四舍五入到最接近的美元。

最后在我的主：

 #include "Money.h"
int main()
{
    //Test round-off operator ^
    Money m14(4 , 19); //round off to the nearest nickel : $4.19 = $4.20
    cout << (m14 ^ NICKEL) << endl;
    Money m15(-3, -1); //round off to the nearest nickel : $-3.01 = $-3.00
    cout << (m15 ^ NICKEL) << endl;
    return 0;
}
Output: 4.22
       -2.-106

编辑：太兴奋了，我忘记了这个问题

如果有人能帮助我展示出了什么问题以及为什么我得到错误的输出，那将不胜感激。谢谢！