使用级别顺序遍历将节点插入二叉树

Inserting a node into a Binary Tree using Level Order Traversal

本文关键字:节点 插入 二叉树 遍历 顺序      更新时间:2023-10-16

我正在尝试编写一个函数,该函数将使用级别顺序遍历将元素插入到二进制树中。我在代码中遇到的问题是,当我在树中插入新节点后打印级别顺序遍历时,它会在无限循环中打印元素。数字1 2 3 4 5 6 7 8在终点站上不停地奔跑。对于如何补救这种情况,我将不胜感激。

typedef struct BinaryTreeNode {
    int data;
    BinaryTreeNode * left;
    BinaryTreeNode * right;
} BinaryTreeNode;

这是打印元素的级别顺序遍历:

void LevelOrder(BinaryTreeNode *root) {
BinaryTreeNode *temp;
std::queue<BinaryTreeNode*> Q {};
if(!root) return;
Q.push(root);
while(!Q.empty()) {
    temp = Q.front();
    Q.pop();
    //process current node
    printf("%d ", temp -> data);
    if(temp -> left) Q.push(temp -> left);
    if(temp -> right) Q.push(temp -> right);
}
}

这是我通过修改层次顺序遍历技术将元素插入到树中的地方

void insertElementInBinaryTree(BinaryTreeNode *root, int element) {
BinaryTreeNode new_node = {element, NULL, NULL};
BinaryTreeNode *temp;
std::queue<BinaryTreeNode*> Q {};
if(!root) {
   root = &new_node;
   return;
}
Q.push(root);
while(!Q.empty()) {
    temp = Q.front();
    Q.pop();
    //process current node
    if(temp -> left) Q.push(temp -> left);
    else {
        temp -> left = &new_node;
        Q.pop();
        return;
    }
    if(temp -> right) Q.push(temp -> right);
    else {
        temp -> right = &new_node;
        Q.pop();
        return;
    }
}
}

主要

int main() {
BinaryTreeNode one = {1, NULL, NULL}; // root of the binary tree
BinaryTreeNode two = {2, NULL, NULL};
BinaryTreeNode three = {3, NULL, NULL};
BinaryTreeNode four = {4, NULL, NULL};
BinaryTreeNode five = {5, NULL, NULL};
BinaryTreeNode six = {6, NULL, NULL};
BinaryTreeNode seven = {7, NULL, NULL};
one.left = &two;
one.right = &three;
two.left = &four;
two.right = &five;
three.left = &six;
three.right = &seven;
insertElementInBinaryTree(&one, 8);
LevelOrder(&one);
printf("n");
return 0;
}

在这条线上

    temp -> left = &new_node;

您正在使temp->left指向一个局部变量,该变量在函数返回后将不再存在。任何访问它的尝试都是未定义的行为。