C++中实现替换游戏场景

Implementation of the replacing game scene in C++

本文关键字：游戏场 替换 实现 C++      更新时间：2023-10-16

我的C++游戏中大约有 10 个场景类。它类似于常规游戏屏幕（菜单屏幕、游戏屏幕、排行榜、选项等）。所以我需要一些技巧来将一个场景替换为另一个场景。我已经阅读了您在此线程中发布给我的所有评论并尝试实施它。现在我有以下代码：

// -----[ main.cpp ]----- //
#include "SceneManager.h"
#include "Scene.h"
int main( int argc, const char * argv[] ) {
    SceneManager *sceneManager = new SceneManager();
    sceneManager->changeScene( 0 );
    delete sceneManager;
    return 0;   
}
// -----[ Scene.h ]----- //
class SceneManager;
class Scene {
public:
    SceneManager *sceneManager;
    void start( SceneManager *sceneManager );
};
// -----[ SceneManager.h ]----- //
#include "Scene.h"
#include "MenuScene.h"
#include "GameScene.h"
class Scene;
class MenuScene;
class GameScene;
class SceneManager {
public:
    Scene* scene;
    void changeScene( short id ) {
        if ( scene != NULL ) {
            delete scene; // to prevent a memory leak
        }
        if ( id == 0 ) {
            scene = new MenuScene();
        } else if ( id == 1 ) {
            scene = new GameScene();
        }
        if (scene) {
            scene->start( this );
        }
    }
};

// -----[ MenuScene.h ]----- //
class MenuScene: public Scene {
public:
    void start( SceneManager *sceneManager ) {
        this->sceneManager = sceneManager;
    }
};
// -----[ GameScene.h ]----- //
class GameScene: public Scene {
public:
    void start( SceneManager *sceneManager ) {
        this->sceneManager = sceneManager;
    }
};

由于错误（XCode 4.6，MacOS X），它不起作用：

Apple Match-O Linker (id) Error
Undefined symbols for architecture x86_64:
  "Scene::start(SceneManager*)", referenced from:
      SceneManager::changeScene(short) in main.o
ld: symbol(s) not found for architecture x86_64

我做错了什么？如何解决？也许有人知道关于这个主题的一些流行问题？

正如评论中提到的，我相信你的设计在概念上需要另一个类。这是一个粗略的例子。

class Scene {
public:
    virtual void start() = 0;
};
class SceneManager {
public:
    void changeScene( short id ) {
        Scene* scene = NULL;
        if ( id == 0 ) {
            scene = new MenuScene(); // undeclared yet
        } else if ( id == 1 ) {
            scene = new GameScene(); // undeclared yet
        }
        if (scene) {
            // TODO: make the scene visible.
            scene->start();
        }
    }
};
class MenuScene: public Scene {
public:
    virtual void start() {
        // Draw menu stuff
    }
};
class GameScene: public Scene {
public:
    void start() {
        // Draw game stuff
    }
};

如果不了解有关特定环境的更多上下文，就很难比这更具体。

相关文章：