将对象数组、对象计数和所需项传递给函数

Passing an array of objects, the count of objects and a desired term to a function

本文关键字:对象 函数 数组      更新时间:2023-10-16

我在完成与 BankAccount 有关的练习时在我的编程书中遇到了一些麻烦。问题问:

创建一个 main() 函数,该函数声明一个包含 10 个 BankAccount 对象的数组。后输入第一个 BankAccount 对象,询问用户是否要继续。提示用户输入 BankAccount 值,直到用户想要退出或输入 10 个 BankAccount 对象(以先到者为准)。对于输入的每个银行账户,显示银行账户详细信息。然后提示用户输入值介于 1 和 40 之间的术语(包括 1 和 40)。继续提示用户,直到输入有效值。然后将 BankAccount 对象的数组、数组中有效对象的计数以及所需的术语传递给一个函数,该函数计算并显示给定年数后以标准利率计算和显示每个 BankAccounts 的值。

我必须使用 3 个公共函数来完成此任务。只有当我尝试计算Interest()时,我才开始遇到问题。如果我尝试将项和计数传递给函数并将其设置为 2 for 循环,我只会收到单个对象的数字和余额。我想我要问的是:如何让程序调用 computeInterest 并为每个 BankAccount 对象运行?

目前,我的代码已设置为可以完美编译和运行,但是,该问题要求将术语和计数发送到函数,而我只发送术语。

我不确定我是否将对象数组发送到函数?这可能是导致麻烦的原因。这已经磨了我大脑好几天了,:(。任何帮助/指示将不胜感激!

#include<iostream>
#include<string>
using namespace std;
// Declaration Section
class BankAccount
{
private:
    int accNum;
    double accBal;
    const static double intRate;
public:
    void enterAccountData(int, double);
    void computeInterest(int);
    void displayAccount();
};
// Implementation Section
const double BankAccount::intRate = 0.03;
void BankAccount::enterAccountData(int num, double bal)
{
    const int MIN_ACC = 1000, MAX_ACC = 9999, MIN_BAL = 0,
    MAX_BAL = 100000;
    cout << "Enter account number: ";
    cin >> num;
    while (num < MIN_ACC || num > MAX_ACC)
    {
        cout << "ERROR: Account number must be between " << MIN_ACC <<
        " - " << MAX_ACC << ".n" << "Enter account number: ";
        cin >> num;
    }
    cout << "Enter account balance: $";
    cin >> bal;
    while (bal < MIN_BAL || bal > MAX_BAL)
    {
        cout << "ERROR: Account balance must be positive and less than $" <<
        MAX_BAL << ".n" << "Enter account balance: $";
        cin >> bal;
    }
    accNum = num;
    accBal = bal;
}
void BankAccount::computeInterest(int YR)
{
    int x;
    double interest;
    for (x = 0; x < YR; ++x)
    {
        interest = accBal * intRate;
        accBal = accBal + interest;
        cout << "Account# " << accNum <<
            ", Balance: $" << accBal << ", Interest: " <<
            intRate << endl;
    }
    cout << endl;
}
void BankAccount::displayAccount()
{
    cout<<"Account: " << accNum <<", Balance: $" << accBal <<
    ", Interest: " << intRate << endl << endl;
}
int main()
{
    const int END = -999, MAX_ACCOUNTS = 10, CONTINUE = 1, MIN_TERM = 1,
    MAX_TERM = 40;
    int i, x, count = 0, num = 0, term = 0;
    double bal = 0;
    BankAccount accounts[MAX_ACCOUNTS];
    do
    {
        count++;
        accounts[count - 1].enterAccountData(num, bal);
        accounts[count - 1].displayAccount();
        cout << "Enter " << CONTINUE << " to proceed, or " << END << " to stop: ";
        cin >> i;
        if (i == END || count == MAX_ACCOUNTS)
        {
            cout << "Enter the term of the accounts (" << MIN_TERM <<
                "-" << MAX_TERM << "): ";
            cin >> term;
            while (term < MIN_TERM || term > MAX_TERM)
            {
                cout << "ERROR: Term must be between " << MIN_TERM <<
                    " - " << MAX_TERM << " inclusive.n" <<
                    "Enter term of the accounts (" << MIN_TERM <<
                    "-" << MAX_TERM << "): ";
                cin >> term;
            }
            for (x = 0; x < count; ++x)
                accounts[x].computeInterest(term);
        }
    } while (i != END && count != MAX_ACCOUNTS);
}

你已经在这样做了 for (x = 0; x < count; ++x) accounts[x].computeInterest(term);

如果确实有必要,您可以在单独的函数中移动该特定代码段,该函数接受 3 个参数:数组accountscountterm

设置 BankAccount 类的方法是每个对象计算自己的兴趣。由于您有多个这样的对象,因此您可以要求每个对象计算自己的兴趣。

希望这有帮助!如果还有其他问题:),请告诉我