卡在一段时间循环C中

stuck in a while loop c

本文关键字：循环 一段时间      更新时间：2023-10-16

我正在为我的C++课做作业。在这个作业中，我需要编写一个程序，从 cin 读取数字，然后对它们求和，当使用 while 循环输入 0 时停止。

我已经编写了代码并得到了我需要的结果。但是，我陷入了一个继续重新打印结果的循环中。谁能给我一些建议，在打印一次结果后结束这个循环？

这是我的代码：

int main ()
{
int i(1), sum(0);
int sum2(0);
const int max(10);
cout << "Enter numbers, one per line. Enter 0 to end:" << endl;
while (i!=0)
{
    cin >> i; 
    sum += i; //add current value of i to sum
    sum2 += 1;
}
while (i==0)
{   
    if (sum < 100) // If total is less than 100
        cout << "Thank you. The total was " << sum << endl 
                 << "The total number of inputs reads: " << sum2 << endl
                 << "The total is less than 100." << endl ;
    else // Else total is greater than 100
            cout << "Thank you. The total was " << sum << endl 
                 << "The total number of inputs reads: " << sum2 << endl 
                 << "The total is greater than 100." << endl ;
}
} //End of Int Main

希望结果没事。抱歉，我不确定如何在每行上发布数字。我还尝试将 while （i==0） 更改为 if 语句 if （i==0），但这会在输入 0 时关闭程序。有人有有用的建议吗？我将不胜感激。^_^

更新：抱歉，我忘了提到我还必须包含一个跟踪输入数的循环计数器、一个确定总值是小于还是大于 100 的注释，以及一个用于确定输入总数的语句。这就是最后 if else 语句的原因。我尝试去掉最后一个 while 语句，因为我知道这是无限循环的原因，但是当我这样做时它不会显示结果。我将代码更改为：

int main ()
{
    int i(1), sum(0);
    int sum2(0);
    const int max(10);
cout << "Enter numbers, one per line. Enter 0 to end:" << endl;
    while (i!=0)
    {
        cin >> i; 
        sum += i; //add current value of i to sum
        sum2 += 1;
    }   
if (sum < 100) // If total is less than 100
            cout << "Thank you. The total was " << sum << endl 
                     << "The total number of inputs reads: " << sum2 << endl
                     << "The total is less than 100." << endl ;
        else // Else total is greater than 100
                cout << "Thank you. The total was " << sum << endl 
                     << "The total number of inputs reads: " << sum2 << endl 
                     << "The total is greater than 100." << endl ;
} //End of Int Main

我的输出应该是

Enter numbers, one per line. Enter 0 to end:
7
8
6
5
5
9
8
0
Thank you. The total was 48.
The total number of inputs read: 8
The total is less than 100.

>i停留在0，并且在退出第一个循环后永远不会更改。 不要使用另一个while循环，只需在之后打印结果。

你的问题是你在循环while (i==0) while loop但i循环内永远不会改变。

while (i==0)  // Infinite loop, i is never change inside the block. 
{   
    if (sum < 100)    // If total is less than 100
        cout << "Thank you. The total was " << sum << endl 
                 << "The total number of inputs reads: " << sum2 << endl
                 << "The total is less than 100." << endl ;
    else            // Else total is greater than 100
            cout << "Thank you. The total was " << sum << endl 
                 << "The total number of inputs reads: " << sum2 << endl 
                 << "The total is greater than 100." << endl;
}

这里根本不需要循环结构。

编辑：你想要的是：

#include <iostream>
using namespace std;
int main(int argc, const char* argv[]) {
  int i, sum, count;
  cout << "Enter numbers, one per line. Enter 0 to end:" << endl;
  while (i!=0) {
    cin >> i; 
    sum += i;
    count++;
  }   
  cout << "Thank you. The total was " << sum << endl 
       << "The total number of inputs reads: " << count << endl;
  if (sum < 100)
    cout << "The total is less than 100." << endl;
  else
    cout << "The total is greater than 100." << endl;
  return 0;
}

演示：

$ ./a.out 
Enter numbers, one per line. Enter 0 to end:
1000
100
10
0
Thank you. The total was 1110
The total number of inputs reads: 4
The total is greater than 100.
$ ./a.out 
Enter numbers, one per line. Enter 0 to end:
1
2
3
0
Thank you. The total was 6
The total number of inputs reads: 4
The total is less than 100.

请注意，计数包括终止0因此您可能希望改为报告count-1。

删除while (i==0) 。 这永远都是事实。

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