将两个常量char*组合在一起

"const"表示"无法更改（*1）"。因此，不能简单地将一个const字符字符串"添加"到另一个（*2）中。您可以将它们复制到一个非常数字符缓冲区中。

const char* a = ...;
const char* b = ...;
char buffer[256]; // <- danger, only storage for 256 characters.
strncpy(buffer, a, sizeof(buffer));
strncat(buffer, b, sizeof(buffer));
// now buffer has the two strings joined together.

由于类似的原因，您尝试使用std:：string失败。你说：

std::string a = "Start";
std::string b = a + " End";

这转化为

b = (std::string)a + (const char*)" End";

这应该是可以的，除了它创建了一个额外的字符串，你可能想要的是

std::string a = "Start";
a += " End";

如果您在执行此操作时遇到编译错误，请将其发布（请确保#包含）。

或者你可以做一些类似的事情：

std::string addTwoStrings(const std::string& a, const std::string& b)
{
    return a + b; // works because they are both strings.
}

以下所有工作：（见现场演示http://ideone.com/Ytohgs)

#include <iostream>
#include <string>
std::string addTwoStrings(const std::string& a, const std::string& b)
{
    return a + b; // works because they are both strings.
}
void foo(const char* a, const char* b)
{
    std::string str = a;
    std::cout << "1st str = [" << str << "]" << std::endl;
    str += " ";
    std::cout << "2nd str = [" << str << "]" << std::endl;
    str += b;
    std::cout << "3rd str = [" << str << "]" << std::endl;
    str = addTwoStrings(a, " ");
    std::cout << "4th str = [" << str << "]" << std::endl;
    str = addTwoStrings(str, b);
    std::cout << "5th str = [" << str << "]" << std::endl;
}
int main()
{
    foo("hello", "world");
}

*1或者更准确地说，"不能原位更改"-你可以在表达式等中使用它，例如

const size_t len = strlen("hello");
size_t newLen = len + strlen("world");
// but this would not be legal:
len += 2; // error: len is const.

2"const chara+const char*b"实际上试图添加两个指针而不是两个字符串，结果将是字符串a的地址加上字符串b的地址，其总和将是某个随机内存位置

char *是指针（"> "和" <"也是），不能将指针添加在一起。

但是，您可以使用+运算符连接C++字符串：

Player::Kill(const std::string& Message)
{
    Console::WriteLine(("> " + Message + " <").c_str());
}

与其连接字符串并创建一个额外的临时对象，为什么不单独输出这3个字符串呢？

Player::Kill(const char* Message)
{
  Console::Write("> ");
  Console::Write(Message);
  Console::WriteLine(" <");
}

既然你说它是C++代码，就这样：

void Player::Kill(std::string const& Message)
{
    Console::WriteLine(("> " + Message + " <").c_str());
}

理想情况下，您的Console::WriteLine()被声明为也接受std::string const&，在这种情况下，不需要进行.c_str()舞蹈。

#include <iostream>
using namespace std;
string string1 = "John";
string string2 = "Smith";
float string1Len = string1.length();
float combinedLen = string1.length() + string2.length();
char combine[string2.length() + string1.length()];
for(int i = 0; i < string1Len; ++i){
    combine[i] = string1[i];
}
for(int i = string1Len; i < combinedLen; ++i){
    combine[i] = string2[i - string1Len];
}
const char * combined = combine;

好吧，可以用const char*进行更改，即使它是const，我们也不能更改它的值，但可以更改它的地址，请查看下面的类以获取参考

    class String
{
private:
    const char* m_Name;
    int m_Size;
public:
    String() :m_Name(" "), m_Size(0) { m_Size = 0; }
    String(const char* name , int size) :m_Name(name),m_Size(size) {}
    String(const char* name) :m_Name(name) {}
    void Display()
    {
        LOG(m_Name);
    }
    int GetSize()
    {
        while (m_Name[m_Size] != '')
        {
            m_Size++;
        }
        return m_Size;
    }
    void Append(const char* nameToAppend)
    {
        //Create an empty char array pointer "*tempPtr" of size = existing const 
        //char name pointer "m_Name"  + const char pointer appending name 
        //"*nameExtention" 
        
        //this array can store both the names 
        int totalSize = 0;
        int nameToAppendSize = 0, existingNameSize = 0;
        while (nameToAppend[nameToAppendSize] != '')
        {nameToAppendSize++;}
        existingNameSize = this->GetSize();
        totalSize = nameToAppendSize + existingNameSize;
        char* tempPtr = new char[totalSize+1];
        //Add  existing const char name pointer "*m_Name"  +  const char pointer 
        //appending name "*nameExtention" to tempPtr,  using a loop 
        
        int currentSize = 0;
        for (int i = 0; i < existingNameSize; i++)
        {   
            tempPtr[currentSize] = m_Name[i];
            currentSize++;
        }
        for (int i = 0; i <= nameToAppendSize; i++)
        {
            if (i == nameToAppendSize)
            {
                tempPtr[currentSize] = ''; // this line tells compiler to stop 
                                             //  writting inside tempPtr 
            }
            else
            {
                tempPtr[currentSize] = nameToAppend[i];
                currentSize++;
            }
        }
        //--------------------------------
        //Now change the address of your const char* with tempPtr
        //This will change the contents of the const char* 
        //--------------------------------
        m_Name = (char*)tempPtr;
    }
};