C++随机数发生器只输出2

代码运行，但随机数生成器仅输出数字2。我输入了漏洞代码，以防有任何我没有想到的因素。有没有一种更方便的方法来工作随机数生成器？

#include <windows.h>
#include <stdio.h>
#include <tchar.h>
#include <iostream>
#include <string>
#include <chrono>
#include <thread>
int Time();
int RanNum1to10();
void main() 
{
time_t now = time(0);
tm *ltm = localtime(&now);
int hour = ltm->tm_hour;
int min = 1 + ltm->tm_min;
int sec = 1 + ltm->tm_sec;
int RanNum = RanNum1to10();
std::string text;
std::getline(std::cin, text);
    {
        if(text.find("hi") != std::string::npos)
        {
            RanNum1to10();
            if (RanNum >= 1 && RanNum <= 4)
            {
                Time();
                if(hour >= 0 && hour <= 11)
                {
                    std::cout << "good morning" << std::endl;
                }
                if(hour >= 12 && hour <= 17)
                {
                    std::cout << "good afternoon" << std::endl;
                }
                if(hour >= 18 && hour <= 23)
                {
                    std::cout << "good evening" << std::endl;
                }
            }
            if (RanNum >= 5 && RanNum <= 6)
            {
                {
                    std::cout << "hey" << std::endl;
                }   
            }
            if (RanNum >= 7 && RanNum <= 8)
            {
                {
                    std::cout << "hello" << std::endl;
                }
            }
            if (RanNum >= 9 && RanNum <= 10)
            {
                {
                    std::cout << "hi" << std::endl;
                }
            }
            std::cout << RanNum;
            std::cout << std::endl;
        }
    }
system("pause");
}
int RanNum1to10()
{
    return (rand() % 10 + 1);
}
int Time()
{
    time_t now = time(0);
    tm *ltm = localtime(&now);
    int hour = ltm->tm_hour;
    int min = 1 + ltm->tm_min;
    int sec = 1 + ltm->tm_sec;
    return hour && min && sec;
}