无法将RInside作为引用传递

Cannot pass RInside as a reference

本文关键字：引用 RInside      更新时间：2023-10-16

所以，我一直在尝试为应用程序使用RInside，但我无法解决这个问题。我读过这个问题，我想我也在做同样的事情：通过RInside'；s'；R'；实例作为类/方法之间的参数

但不知何故，它不起作用，下面是一个代码示例：

pair<Rcpp::NumericVector,int> kmedoids (RInside & R, vector<int> alerts) {
    R["M"] = alerts;
    string txt = "library(cluster);"
                 "result <- clara(M, 2);";
    R.parseEvalQ(txt);
    Rcpp::NumericVector result((SEXP) R.parseEval("res <- result$cluster"));
    Rcpp::NumericMatrix clusinfo1 ((SEXP) R.parseEval("clusinfo <- result$clusinfo"));
    int biggerCluster = getBiggerCluster(clusinfo1);
    pair <Rcpp::NumericVector,int> par;
    par.first = result;
    par.second = biggerCluster;
    return par;
}

RInside R(int argc, char *argv[]);
pair<Rcpp::NumericVector,int> srcIPKmedoid = kmedoids(R, srcIPAmounts);
pair<Rcpp::NumericVector,int> dstIPKmedoid = kmedoids(R, dstIPAmounts);
pair<Rcpp::NumericVector,int> attackClassKmedoid = kmedoids(R, attackClassAmounts);

我得到的错误：

/home/renato/workspace/tilera/oads/AM/src/AM.cpp:442:73: error: invalid initialization    of non-const reference of type ‘RInside&’ from an rvalue of type ‘RInside (*)(int, char**)’
/home/renato/workspace/tilera/oads/AM/src/AM.cpp:302:31: error: in passing argument 1 of ‘std::pair<Rcpp::Vector<14>, int> kmedoids(RInside&, std::vector<int>)’
/home/renato/workspace/tilera/oads/AM/src/AM.cpp:443:73: error: invalid initialization of non-const reference of type ‘RInside&’ from an rvalue of type ‘RInside (*)(int, char**)’
/home/renato/workspace/tilera/oads/AM/src/AM.cpp:302:31: error: in passing argument 1 of ‘std::pair<Rcpp::Vector<14>, int> kmedoids(RInside&, std::vector<int>)’
/home/renato/workspace/tilera/oads/AM/src/AM.cpp:444:85: error: invalid initialization of non-const reference of type ‘RInside&’ from an rvalue of type ‘RInside (*)(int, char**)’
/home/renato/workspace/tilera/oads/AM/src/AM.cpp:302:31: error: in passing argument 1 of ‘std::pair<Rcpp::Vector<14>, int> kmedoids(RInside&, std::vector<int>)’

我做的正是Dirk的Qt例子，把RInside作为参考，我做错了什么？

提前谢谢。

RInside R(int argc, char *argv[]);不是一个对象，而是一个函数声明。请改用RInside R(argc, argv);。

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