运算符>>在Visual C++ 2010中工作，但在Linux上不能使用G++。

operator>> works in Visual C++ 2010 but not G++ on Linux

本文关键字：gt 不能 Linux G++ 但在 工作 Visual C++ 2010 运算符      更新时间：2023-10-16

我有以下问题:

我的代码与visual c++ 2010工作良好，但是当我在Linux上编译它时，它被编译了，但是有些东西不起作用:

这是Vector输入operator>>:

istream& operator>>(istream& in,Vector& x)
{
char a;
in.sync();
a=in.get(); //gets the '['
for(int i=0;i<x._n;i++)
    {
        in>>x._vector[i];
        if ((i+1)!=x._n)
        a=in.get(); //gets the ','
    }
in>>a; //gets the ']'
return in;
}

_vector点在Complex数数组上，Complex的operator>>工作正常

输入应该是这样的:

[2+3i,9i,1]

当我在visual c++ 2010上运行此代码时，它工作了，看起来像这样:

cin>>v; // [1+1i,2]
cin>>u; // [10,5i]
cout<<v<<endl; //prints: [1+i,2]
cout<<u<<endl; //prints: [10,5i]

当我在Linux上运行相同的代码时，在第一个数组[1+1i,2]之后，程序结束:

[1+1i,2]  //this is the input
[6.105e-317+6.105e-317i,6.105e-317+6.105e-317i]
[6.105e-317+6.105e-317i,6.105e-317+6.105e-317i]

现在我甚至不能写另一个Vector

顺便说一句:这是向量。h

#ifndef _VECTOR_
#define _VECTOR_
#include <iostream>
using namespace std;
#include "Complex.h"
class Vector
{
private:
    int _n;
    Complex *_vector; //points on the array of the complex numbers
public:
    Vector(int n); // "Vector" - constructor of Vector with n instants
    Vector(const Vector& x);  // "Vector" - copy constructor of Vector with n instants
~Vector(); // "~Vector" - destructor of Vector
const Vector& operator=(const Vector& x); // "operator=" - operates "=" for Vector
Complex& operator[](const int index); // "operator[]" - choose an instant by his index in the _vector
const Vector operator+(const Vector& x) const; // "operator+" - operates "+" between two vectors
const Vector operator-(const Vector& x) const; // "operator-" - operates "-" between two vectors
const Vector operator*(double scalar) const; // "operator*" - multiplate all of the instants of the vector by the scalar
friend const Vector operator*(double scalar,const Vector& x); // "operator*" - multiplate all of the instants of the vector by the scalar
const Complex operator*(const Vector& x) const; // "operator*" - operates "*" between two vectors
const Vector& operator+=(const Vector& x); // "operator+=" - operates "+=" for the instant
const Vector& operator-=(const Vector& x); // "operator-=" - operates "-=" for the instant
friend ostream& operator<<(ostream& out,const Vector& x); // "operator<<" - prints the vector
friend istream& operator>>(istream& in,Vector& x); // "operator<<" - gets the vector
const double operator!() const; // "operator!" - returns the the instant in the definite value of the vactor that his definite value is the highest (in the Vector)
};
    #endif

，这里是我定义Vector的构造函数的地方:Vector.cpp 

#include <iostream> 
using namespace std;
#include <math.h>
#include "Complex.h"
#include "Vector.h"
// "Vector" - constructor of Vector with n instants
Vector::Vector(int n)
{
    _vector=new Complex[n]; //new vector (array) of complex classes
    _n=n;
}

有人能帮我吗?

我想问题出在你给in.sync()的电话上。

刷新输入缓冲区，也就是说，它丢弃当前在istream缓冲区中的任何数据。确切地放入缓冲区的内容取决于a)您的平台和b)在调用operator>>之前所做的操作。

至于b)，这就是为什么从operator>>调用sync是错误的，但这是"你的问题"。

对于a)，您应该知道UNIX系统在istream获得发言权之前，在操作系统级别为控制台文本输入执行行缓冲。您想要刷新的数据可能在操作系统缓冲区中，而不是在istream的缓冲区中。

如果你只是想跳过空白，你应该使用in >> std::ws;

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