基于用户大小的数组函数,如果值大于90,则输出一些内容

User sized based array function to print out something if there are values higher than 90

本文关键字:大于 如果 输出 函数 用户 于用户 数组      更新时间:2023-10-16

我设置了一个基于用户大小的数组来输入一些分数,并打印出最高分和最低值以及平均值。我还想使用boolen函数来打印出是否有任何a成绩(分数高于90),但是我不太确定如何编码。我在下面尝试了getAScores函数,但它不起作用。

#include <iostream> 
using namespace std; 
#include <iomanip>  
#include <cstdlib>
int compare(const void* pa, const void* pb) 
{ 
  const int& a = *static_cast<const int*>(pa); 
  const int& b = *static_cast<const int*>(pb); 
  if (a < b) return -1; // negative if a<b 
  if (a > b) return 1; // positive if a>b 
  return 0; // 0 for tie 
} // compare 
double getAverage(int* score, int n) 
{ 
  int sum = 0; 
  int i = 0; 
  for (i = 0; i < n; i++) 
    sum += score[i]; 
  double average = double(sum) / n; 
  return average; 
} // getAverage 
//Boolen Function to see if there are A grades present 
bool getAGrades(int* score) 
{ 
  int i = 0;
  if (score[i] >= 90){
  return true;
  cout << "there is at least one A"<<endl;
  }else {
   return false;
  cout<<" No A Grades "<<endl;
}
}
int main() 
{  
  int size;
  cout << "How many scores? ";
  cin >> size;
  cin.ignore(1000, 10);
  int* score = new int[size];  
  int i; // loop counter 
  for (i = 0; i < size; i++) 
  { 
    cout<< "Enter a number: ";
    cin >> score[i]; 
    cin.ignore(1000, 10); 
  } // for 
qsort(score, size, sizeof(int), compare); 
for (int i = 0; i < size; i++) {
    cout << score[i] << ' ';
  }
  cout <<endl;
  cout << "Lowest score  = " << score[0] << endl;
  cout << "Highest score = " << score[size-1] << endl;
  cout << fixed << setprecision(1);
  cout << "Average = " << getAverage(score, size) << endl; 
  //this is where i want it to print if there are a grades or not
  getAGrades(score);

  return 0; 
} // main

您需要使用循环来查看所有索引(就像您在getAverage中所做的那样)。这需要getAGrades知道数组的大小。

另外,请注意,将cout放在return之后是没有意义的-它将永远不会被执行。

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