成员函数指针作为模板参数的问题

感谢dyp纠正了我在语法上的可怕挣扎，我完成了我打算做的事情:

#include <memory>
#include <functional>
#include <map>
#include <tuple>
template <typename R, typename T, typename... Args>
std::function<R(Args...)> memoizeMemberFunction (R (T::*f)(Args...), T* t) {
    auto cache = std::make_shared<std::map<std::tuple<T*, Args...>, R>>();
    return ([f, cache, t](Args... args) {
        const std::tuple<T*, Args...> tuple(t, args...);
        if (cache->find(tuple) == cache->end())
            (*cache)[tuple] = (t->*f)(args...);  // Insert 'tuple' as a new key in the map *cache.
        return (*cache)[tuple];
    });
}
template <typename R, typename T, typename... Args>
std::function<R(Args...)> memoizeConstMemberFunction (R (T::*f)(Args...) const, const T* t) {
    auto cache = std::make_shared<std::map<std::tuple<const T*, Args...>, R>>();
    return ([f, cache, t](Args... args) {
        const std::tuple<const T*, Args...> tuple(t, args...);
        if (cache->find(tuple) == cache->end())
            (*cache)[tuple] = (t->*f)(args...);  // Insert 'tuple' as a new key in the map *cache.
        return (*cache)[tuple];
    });
}
template <typename Class, typename Fptr, Fptr> struct MemberFunctionMemoizer;
template <typename Class, typename Fptr, Fptr> struct ConstMemberFunctionMemoizer;
template <typename Class, typename R, typename... Args, R (Class::*F)(Args...) const>
struct ConstMemberFunctionMemoizer<Class, R (Class::*)(Args...) const, F> {
    static std::function<R(Args...)>& get (const Class* p) {
        static std::function<R (Args...)> memoizedF (memoizeConstMemberFunction(F, p)); 
        return memoizedF;
    }
};
template <typename Class, typename R, typename... Args, R (Class::*F)(Args...)>
struct MemberFunctionMemoizer<Class, R (Class::*)(Args...), F> {
    static std::function<R(Args...)>& get (Class* p) {
        static std::function<R (Args...)> memoizedF (memoizeMemberFunction(F, p)); 
        return memoizedF;
    }
};
// Testing
#include <iostream>
#include <vector>
struct FibonacciCalculator {
    std::vector<unsigned long> computed;
    unsigned long calculate (unsigned num) const {
        using F = ConstMemberFunctionMemoizer<FibonacciCalculator, unsigned long (FibonacciCalculator::*)(unsigned) const, &FibonacciCalculator::calculate>;  // 'decltype(&FibonacciCalculator::calculate)' can be used in place of 'unsigned long (FibonacciCalculator::*)(unsigned) const'.
        return (num < 2) ? num : F::get(this)(num - 1) + F::get(this)(num - 2);
    }
    unsigned long calculateAndStore (unsigned num) {
        using F = MemberFunctionMemoizer<FibonacciCalculator, unsigned long (FibonacciCalculator::*)(unsigned), &FibonacciCalculator::calculateAndStore>;  // 'decltype(&FibonacciCalculator::calculateAndStore)' can be used in place of 'unsigned long (FibonacciCalculator::*)(unsigned)'.
        const unsigned long result = (num < 2) ? num : F::get(this)(num - 1) + F::get(this)(num - 2);
        computed.push_back(result);
        return result;
    }
};
int main() {
    FibonacciCalculator fib;
    for (unsigned i = 1; i < 20; i++)
        std::cout << fib.calculate(i) << ' ';  // 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181
    std::cout << 'n';
    for (unsigned i = 1; i < 20; i++)
        std::cout << fib.calculateAndStore(i) << ' ';  // 1 1 2 3 5 8 13 21 34 55 89 144 233 377 610 987 1597 2584 4181
    std::cout << 'n';
    for (unsigned long x : fib.computed)
        std::cout << x << ' ';  // 1 1 0 1 1 2 2 3 3 5 5 8 8 13 13 21 21 34 34 55 55 89 89 144 144 233 233 377 377 610 610 987 987 1597 1597 2584 2584 4181
    std::cout << 'n';  
}

最大的问题是你试图记住一个签名函数:

unsigned long calculate();

，但你调用记忆缓存的返回函数F::get(this)与num - 1或num - 2。

换句话说:记忆依赖于"使用相同参数调用的函数产生相同的返回值"这一事实，但是你记忆的函数不接受任何参数(这本身没有错)，但是你也不应该传递任何参数给它。

当前的FibonacciCalculator类不能使用记忆，因为它目前是实现的。

我已经实现了一个可能做你希望做的事;它计算斐波那契数和，它记忆成员函数调用…注意:在memoizeMemberFunction()中有额外的"噪音"，但这是显示它正在工作的输出-你会在输出中看到函数调用被使用了两次，并且只计算了一次。

#include <iostream>
#include <memory>
#include <functional>
#include <map>
#include <tuple>
template <typename R, typename T, typename... Args>
std::function<R(Args...)> memoizeMemberFunction (R (T::*f)(Args...), T* t) {
    auto cache = std::make_shared<std::map<std::tuple<T*, Args...>, R>>();
    return [f, t, cache](Args... args) {
        const std::tuple<T*, Args...> tuple(t, args...);
        if (cache->find(tuple) == cache->end()) {
            (*cache)[tuple] = (t->*f)(args...);  // Insert 'tuple' as a new key in the map *cache.
            std::cout << "Computed f(";
            int dummy[sizeof...(Args)] = { (std::cout << args << ", ", 0)... };
            std::cout << ") = " << (*cache)[tuple] << std::endl;
        }
        std::cout << "Using f(";
        int dummy[sizeof...(Args)] = { (std::cout << args << ", ", 0)... };
        std::cout << ") = " << (*cache)[tuple] << std::endl;
        return (*cache)[tuple];
    };
}
struct FibonacciCalculator {
    unsigned long num;
    unsigned long calculate(unsigned long n = (unsigned long)-1) {
        static auto memoizedF (memoizeMemberFunction(&FibonacciCalculator::calculate, this));
        if( n==(unsigned long)-1 )
            return memoizedF(num);
        return (n < 2) ? n : memoizedF(n-1) + memoizedF(n-2);
    }
};
int main() {
    FibonacciCalculator fib{ 10 };
    std::cout << fib.calculate() << 'n';
}