GCC中包含的文件更详细的模式

我正在尝试编译别人的项目。我已经设法在windows下构建它，这意味着它是可编译的，但现在我在Linux上挣扎。具体来说，我得到了一个文件的错误:

#ifndef _LOGGER_H_2011_27_02_ 
#define _LOGGER_H_2011_27_02_ 
//  logger
#include <log4cplus/logger.h>
#include <iomanip>
#define LOG_TRACE(logger, msg) LOG4CPLUS_TRACE(logger, 
    "[@" << std::hex << (size_t)this << "] " << std::dec << msg);
#define LOG_DEBUG(logger, msg) LOG4CPLUS_DEBUG(logger, 
    "[@" << std::hex << (size_t)this << "] " << std::dec << msg);
// I erased repetitive declarations for WARN, FATAl etc...

代码本身对我来说没有意义，表达式"[@" <<有点疯狂，但没关系，它应该编译。我得到的错误是:

source/repository/../query/../loader/../common/logger.h:30:64: error: ‘LOG4CPLUS_ERROR’ was not declared in this scope
     "[@" << std::hex << (size_t)this << "] " << std::dec << msg);

也:

source/repository/Repository.cpp: In member function ‘void W3TTServer::Repository::cleanupSessions()’:
source/repository/Repository.cpp:82:64: error: invalid operands of types ‘const char [33]’ and ‘long int’ to binary ‘operator<<’
  LOG4CPLUS_TRACE(logger, "Cleaning up inactive sessions..." << sessionCleanupTimer);

我启用了详细模式，但这是一个笑话，真的，我得到的是包含目录列表:

#include <...> search starts here:
 /usr/local/ssl/include
 /usr/include/c++/4.9
 /usr/include/x86_64-linux-gnu/c++/4.9
 /usr/include/c++/4.9/backward
 /usr/lib/gcc/x86_64-linux-gnu/4.9/include
 /usr/local/include
 /usr/lib/gcc/x86_64-linux-gnu/4.9/include-fixed
 /usr/include/x86_64-linux-gnu
 /usr/include
End of search list.

log4cplus库安装在/usr/include/log4cplus/中，由于没有关于丢失头文件的错误，我假设<log4cplus/logger.h>加载得很好。为了验证这一点，我需要一个包含文件的列表来查看位置是否正确。

如何在GCC中获得包含文件的列表?