编写程序从数组中删除重复项

我正在研究从数组中删除重复项的程序，我在这里使用三个函数:一个用于输入大小和数字，第二个函数用于删除重复项并返回没有重复项的数字，第三个函数只是一个报告显示大小和新数字，但我有问题，我不知道在报告或菲利普错误中我认为在哪一步:

函数‘int main()’:从‘int*’到‘int’的转换无效，初始化‘void report(int, int)’的参数1

#include <iostream>
using namespace std;
const int size = 100;
void phillip(int[], int & );
/* Preconditions: Array of base type in declared and int varuable declared
   postconditions: the array is filled with values supllied by the user at
   the keybord. the user is assked how many values they want - this value is
   given to the second argument.
*/
int remdubs(int[], int noel);
/* Preconditions: An array of basetype int that  has noel values.
   postconditions: The number of unique elemts in the array is returned. The function removes all dubplicates inside the array.
*/
void report(int s, int d);
int main()
{
    int ruby[size];
    int numele, numuniq;
    phillip(ruby, numele);
    numuniq = remdubs(ruby, numele);
    report(ruby, numuniq);
    return 0;
}
void phillip(int[], int& )
{
    int s;
    cout << "nHow many values you want? ";
    cin >> s;
    cout << "nPlease input 10 integers, hitting return after each one n";
    for (int i = 0; i < s; i++)
    {
        int num;
        cin >> num;
    }
}
int rembups(int sapphire[], int noel)
{
    for (int i = 0; i < noel; i++)
    {
        for (int j = i + 1; j < noel; j++)
        {
            if (sapphire[i] == sapphire[j])
            {
                for (int k = j; k < noel; k++)
                    sapphire[k] = sapphire[k + 1];
                noel--;
                j--;
            }
        }
    }
    return noel;
}
void report(int s, int d)
{
    cout << "nYou entered " << s << "distinct numbers: " << d;
}